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2 years ago

How does gravity affect speed

Physics

2 answers:

Sidana [21]2 years ago

6 0

Answer:

It is heavy which affects the speed of things.

Explanation:

mixas84 [53]2 years ago

3 0

Answer:

When objects fall to the ground, gravity causes them to accelerate. ... Gravity causes an object to fall toward the ground at a faster and faster velocity the longer the object falls. In fact, its velocity increases by 9.8 m/s2, so by 1 second after an object starts falling, its velocity is 9.8 m/s

Explanation:

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An elevator is being pulled up from the ground floor to the third floor by a cable. The cable is exerting 4500 newtons of force

Delicious77 [7]

Answer:

The gravitational force on the elevator = 4500N

Explanation:

The given parameters are;

The force applied by the elevator, F = 4500 N

The acceleration of the elevator = Not accelerating

From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows;

F = W + Mass of elevator × Acceleration of elevator

∴ F = W + Mass of elevator × 0 = W

F = 4500 N = W

The net force on the elevator is F - W = 0

The gravitational force on the elevator = W = 4500N.

3 0

2 years ago

Which statements apply to transverse waves? Check all that apply.

Levart [38]

Correct Answers:

- The waves have a trough

- the waves have a crest

- the energy that is transferred move in a perpendicular direction

- particles move in an up and down motion

8 0

2 years ago

Read 2 more answers

An astronaut exploring a distant solar system lands on an unnamed planet with a radius of 2530 km. When the astronaut jumps upwa

Natali [406]

Answer:

1.38*10^18 kg

Explanation:

According to the Newton's law of universal gravitation:

$F=G*\frac{m_a*m_p}{r^2}$

where:

G= Gravitational constant (6.674×10−11 N · (m/kg)2)

ma= mass of the astronaut

mp= mass of the planet

$F=m_a.a\\(v_f )^2=(v_o)^2+2.a.\Delta y\\\\a=\frac{(v_f)^2-(v_o)^2}{2.\Delta y}\\\\a=\frac{(0)^2-(4.29m/s)^2}{2.0.64m}=14.38m/s^2\\\\F=m_a*14.38m/s^2$

so:

$m_a*14.38m/s^2=(6.674*10^{-11}N.(m/kg)^2)*\frac{m_a.m_p}{(2.530*10^3m)^2}\\m_p=\frac{14.38m/s^2(2.530*10^3m)^2}{(6.674*10^{-11}N.(m/kg)^2)}\\\\m_p=1.38*10^{18}kg$