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Helen [10]
3 years ago
7

Many objects orbit the sun in the Kuiper belt. should such an object be called a comet if it does not have a tail? develop an ar

gument to support your opinion.
first to answer ill name you brainliest!!!
Physics
1 answer:
Digiron [165]3 years ago
7 0

Comets are cosmic snowballs of frozen gasses, rock and dust that orbit the sun. When frozen, they are the size of a small town. When a comet's orbit brings it close to the sun, it heats up and spews dust and gasses that form a tail that stretches away from the sun fr millions of miles. There are probably billions of comets orbiting our sun in the Kuiper Belt and even more distant Oort Cloud. Comets have right for its name and had best to orbit the sun in the Kuiper Belt.

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The particle in the atom with a negative charge is the ______<br> Answer here
NISA [10]

Answer:

Explanation:

The electron has a negative charge. Proton is positive and neutron is neutral.

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3 years ago
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Moment of inertia: A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length
LekaFEV [45]

Answer:

B.Less than

Explanation:

We are given that

Mass of each object=m

Length of rod=r

I_1=Moment of inertia of the dumbbell shaped object with respect to an axis passing through the center of the rod and perpendicular to it.

I_2=Moment of inertia with respect to an axis passing through one of the masses.

I_1=\frac{mr^2}{4}+\frac{mr^2}{4}

I_1=\frac{2mr^2}{4}=\frac{1}{2}mr^2

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I_2>I_1

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B.Less than

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3 years ago
If you place 48 cm object 15 m in front of a convex mirror of focal length 5 m, what is the magnification of the image?
Arisa [49]

Answer:

m = 0.25

Explanation:

Given that,

Object distance, u = -15cm

Height of the object, h = 48

Focal length, f = cm

We need to find the magnification of the image.

Let v is the image distance. Using mirror's equation.

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\=\dfrac{1}{5}-\dfrac{1}{(-15)}\\\\=3.75\ cm

Magnification,

m=\dfrac{-v}{u}\\\\=\dfrac{-3.75}{-15}\\\\=0.25

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3 years ago
Which type of wave can only be transmitted through matter?
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8 0
3 years ago
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g During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approxi
Alisiya [41]

Answer:

The force is F = 0.1441 \  N

Explanation:

From the question we are told that

   The volume of blood ejected is  V_b  =  65cm^3 = 65*10^{-6} \  m^3

    The velocity of the ejected blood is  v  = 98 cm/ s = 0.98 \  m/s

    The mass density of blood is  \rho = 1060 \  kg/m^3

    The heart rate is  R  =  61 bpm(beats \  per \  miunite) = \frac{61}{60} = 1.0667\  bps

Generally the average force exerted is mathematically represented as

     F = 2 *  \rho *  V_b *  R *  v

=>   F = 2 * 1060  *  (65*10^{-6}) *1.0667   *   0.98

=>   F = 0.1441 \  N    

8 0
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