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vlada-n [284]
3 years ago
12

Add or subtract as indicated:

Physics
1 answer:
zzz [600]3 years ago
7 0
D. 8.12×10^7g - 6.20×10^6g
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Is it true or false that air pollution only occurs as a result of human activity
gregori [183]
Hi alexander it is very true air pollution is only caused by human activity

8 0
3 years ago
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An aluminum cylinder weighing 30 N, 6 cm in diameter and 40 cm long, is falling concentrically through a long vertical sleeve of
Georgia [21]

Answer: Velocity terminal = 0.093m/s

Explanation:

1. We start by evaluating the gap distance between the two cylinders as h = R(sleeve) - R(cylinder)

= (0.0604/2 - 0.06/2)m

= 2×10^-4

Surface are of the cylinder in the drop, which is required in order to evaluate the shearing stress can be expressed as A(cylinder) = π.d.L

= (π×0.06×0.4)m²

= 0.075m²

Since the force of the cylinder's weight is going to balance the shearing force on the walls, we can express the next equation and derive terminal velocity from it.

Shearing stress = u×V.terminal/h = 0.86×V/0.0002

= 4300Vterminal

Therefore, Fw = shearing stress × A

30N = 4300Vterminal × 0.075

V. terminal = 30/4300 m.s

V. terminal = 0.093m/s

4 0
3 years ago
A refrigerator has a mass of 88 kg. What is the weight of the refrigerator?
posledela

Answer:

I don't think the information is complete

6 0
2 years ago
Light rays travel from one medium into another and refract away from the boundary. What changes about the light to cause this re
vaieri [72.5K]

Answer:

a

Explanation:

I think its a its speed increases.....

8 0
3 years ago
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What is the number of electrons that move past a point in a wire carrying 500 A of current in 4.0 minutes
mr Goodwill [35]
The current is defined as the amount of charge Q that passes through a given point of a wire in a time \Delta t:
I= \frac{Q}{\Delta t}
Since I=500 A and the time interval is
\Delta t=4.0 min=240 s
the charge is
Q=I \Delta t=(500 A)(240 s)=1.2 \cdot 10^5 C

One electron has a charge of q=1.6 \cdot 10^{-19}C, therefore the number of electrons that pass a point in the wire during 4 minutes is
N= \frac{Q}{q}= \frac{1.2 \cdot 10^5 C}{1.6 \cdot 10^{-19}C}=7.5 \cdot 10^{23} electrons
3 0
3 years ago
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