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Romashka-Z-Leto [24]
3 years ago
9

An ocean liner is cruising at 10 meters/second and is about to approach a stationary ferryboat. A parcel is released from the oc

ean liner from a height of 5.5 meters above the ferryboat’s deck. Calculate the distance at which the ferryman should position the boat from the point horizontally below the point of release so that the parcel lands inside the boat.
Physics
1 answer:
Afina-wow [57]3 years ago
4 0
The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.

First, we determine how long the parcel will fall using:

s = ut + 1/2 at²

where s will be the height, u is the initial vertical velocity of the parcel (0), t is the time of fall and a is the acceleration due to gravity. 

5.5 = (0)(t) + 1/2 (9.81)(t)²
t = 1.06 seconds

Now, we may use this time to determine the horizontal distance covered by the parcel by using:
distance = velocity * time

The horizontal velocity of the parcel will be equal to the horizontal velocity of the cruise liner.

Distance = 10 * 1.06
Distance = 10.6 meters

The boat should be 10.6 meters away horizontally from the point of release.
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choli [55]

Answer:

we know thatv

F =m×a

so, m = F/a

m =30/7

m=30/7kg

3 0
2 years ago
Lawson's criterion states that the product of ion density and confinement time must exceed a certain number before a break-even
LekaFEV [45]

According to Lawson's criterion, the outcome is determined by the product of ion density and confinement time because the temperature must be maintained for a sufficient confinement time and with a sufficient ion thickness to obtain a net gain of power from a fusion reaction.

<h3>What are Lawson's criterion?</h3>
  • The overall conditions that must be met in order to produce more energy than is required for plasma heating are usually expressed in terms of the product of ion density and confinement time, a condition known as Lawson's criterion.
  • In nuclear fusion devices, confinement time is defined as the amount of time the plasma is kept at a temperature above the critical ignition temperature.
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brainly.com/question/28303495

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7 0
1 year ago
four forces act on an object of mass 100kg, they are 12N(N), 70N(S), 33N(E), 10N(w). calculate the reseulting acceleration of th
trapecia [35]

Answer:

0.62 m/s² at 68° S of E

Explanation:

Net force north = 12 - 70 = -58 N

Net force east = 33 - 10 = 23 N

Net force = √(-58² + 23²) = 62.3939... N

acceleration = F/m = 62.3939/100 = 0.623939... ≈ 0.62 m/s²

θ = arctan(-58/23) = -68.3691... ≈ 68° S of E

6 0
3 years ago
I need help!!!! I don’t understand physical science at all.
allochka39001 [22]
B is the correct answer
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2 years ago
Scott cuts a one meter long wire into five equal parts. What is the length of each part of the wire? (2 points) 0.02 centimeters
kompoz [17]
20 centimeters. 100 centimeters in a meter. 100/5= 20
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3 years ago
Read 2 more answers
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