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Deffense [45]
3 years ago
11

Help pls and. No links pls

Physics
2 answers:
Rainbow [258]3 years ago
8 0

Answer:

false.......,.....,...........

aev [14]3 years ago
7 0

Answer:

the answer to this question will be False

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Which of the following statements is FALSE about collisions? (Consider Newton's Laws an the Conservation of Momentum.)
pantera1 [17]

<u>The following statements are false about collisions: </u>

  • The velocity change of two respective objects involved in a collision will always be equal.
  • Total momentum is always conserved between any two objects involved in a collision.

Answer: Option B, and D

<u>Explanation: </u>

In any collisions, equal amount of net force will be acted upon the colliding objects due to the third law of Newton, irrespective of the significance difference in mass of the objects. Similarly, they can also have different acceleration values during collision of two objects if the masses are identical.

But the statements regarding the equal change in velocity of two objects respectively involved in collision always is false, as the conservation of momentum is applicable for isolated system only. So it is true for only isolated system and not in all the systems.

The same reason goes for falsifying the fourth statement which states that total momentum is always conserved between two objects involved in a collision as this statement is only true for isolated system where the conservation of momentum can be applied. Thus the second and fourth statement is false regarding collision.

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3 years ago
It might be a good idea to talk to your parents about alcohol because:
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might stumble upon this substance one day and be curious about what it does.

5 0
3 years ago
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The element carbon has 3 naturally occurring isotopes. About 99% of carbon isotopes are C-12, about 1% are C-13, and a tiny amou
mezya [45]
Average atomic mass of carbon is 12.01 amu
3 0
4 years ago
Will give brainliest! 50 points!!!
tatiyna

Answer:

C

Im not totally sure but that's what my science teacher taught me sorry if is wrong

6 0
3 years ago
Calculate the electric field strength at a point at which a test charge of 0.30 coulombs experiences a force of 5.0 newtons.
SVEN [57.7K]

The strength of electric field E is 17 N / C.

<u />

<u>Explanation:</u>

Electric field strength is defined as the force per unit charge acting at a point in the given field. The equation for the strength of the electric field is given by

                     E = F / q

where E represents the electric field strength,

           F represents the force in newton,

           q represents the charge in coulomb.

Given the charge q = 0.30 coulombs

                   force F = 5.0 N

Electric field strength E = force / charge

                                        = 5.0 / 0.30

                                    E  = 16.66 = 17 N / C.

5 0
3 years ago
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