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3 years ago

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! EXTRA POINTS DONT SKIP:((

Engineering

2 answers:

Trava [24]3 years ago

8 0

Answer:

Explanation:

Have a good day my friend

ziro4ka [17]3 years ago

6 0

Answer:

it is 16

Explanation:

i looked it up

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A submarine submerges by admitting seawater (S = 1.03) into its ballast tanks. The amount of water admitted is controlled by air

ser-zykov [4K]

Answer:

Explanation:

Fw= y looking symbol sea water (2010.62-168171.2727/h+32.935)ft^3

6 0

3 years ago

What are the three most common types of relearn procedures?

WITCHER [35]

Answer:

The three types of relearn procedures are auto relearn, stationary and OBD.

Explanation:

In TPMS system, after the direct service like adjustment of air pressure, tire rotation or replacement of sensors etc, is performed then maximum vehicle often needs TPMS system relearn that needs to be performed.

For performing these relearn procedure, there are mainly three types:

auto relearn
stationary relearn
OBD

After applying the relearn process, the TPMS system will again be in proper function.

8 0

3 years ago

Steam enters a steady-flow adiabatic nozzle with a low inlet velocity (assume ~0 m/s) as a saturated vapor at 6 MPa and expands

Sergio [31]

Yea bro I don’t really know

7 0

2 years ago

Which option best describes a way engineers can provide maintenance, diagnoses, upgrades, or duplicates even for products they d

guajiro [1.7K]

Answer:

Reverse Engineering

Explanation:

Just took the test

4 0

2 years ago

A water pump delivers 3 hp of shaft power when operating. If the pressure differential between the outlet and the inlet of the p

Natali [406]

Answer:

Mechanical Efficiency = 83.51%

Explanation:

Given Data:

Pressure difference = ΔP=1.2 Psi

Flow rate = $V=8ft^3/s\\$

Power of Pump = 3 hp

Required:

Mechanical Efficiency

Solution:

We will first bring the change the units of given data into SI units.

$P=1.2*6.895 = 8.274KPa\\V=8*0.00283=0.226 m^3/s\\P=3*0.746=2.238KW$

Now we will find the change in energy.

Since it is mentioned in the statement that change in elevation (potential energy) and change in velocity (Kinetic Energy) are negligible.

Thus change in energy is

$=(Mass * change in P)/density\\= \frac{M*P}{p}\\\\$

As we know that Mass = Volume x density

substituting the value

Energy = Volume * density x ΔP / density

Change in energy = Volumetric flow x ΔP

Change in energy = 0.226 x 8.274 = 1.869 KW

Now mechanical efficiency = change in energy / work done by shaft

Efficiency = 1.869 / 2.238

Efficiency = 0.8351 = 83.51%

5 0

3 years ago

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! EXTRA POINTS DONT SKIP:((