Answer:
7500 N/m²
Explanation:
From the question given above, the following data were obtained:
Force (F) = 300 N
Area (A) = 400 cm²
Pressure (P) =?
Next, we shall convert 400 cm² to m². This can be obtained as follow:
1×10⁴ cm² = 1 m²
Therefore,
400 cm² = 400 cm² × 1 m² / 1×10⁴ cm²
400 cm² = 0.04 m²
Finally, we shall determine the pressure. This can be obtained as follow:
Force (F) = 300 N
Area (A) = 0.04 m²
Pressure (P) =?
P = F/A
P = 300 / 0.04
P = 7500 N/m²
Answer:
a. +10.9μC
b. 0.600N and downward
Explanation:
To determine the magnitude of the charge, we use the force rule that exist between two charges which us expressed as
F=(kq₁q₂)/r²
since q₁=-0.55μC and the force it applied on the charge above it is upward,we can conclude that the second charge is +ve, hence we calculate its magnitude as
q₂=Fr²/kq₁
q₂=(0.6N*0.3²)/(9*10⁹*0.55*10⁻⁶)
q₂=0.054/4950
q₂=1.09*10⁻⁵c
q₂=10.9μC.
Hence the second charge is +10.9μC
b. From the rule of charges which state that like charges repel and unlike charges attract, we can conclude that the two above charges will attract since they are unlike charges. Hence the direction of the force will be downward into the second charge and the magnitude of the force will remain the same as 0.600N
Answer:
B. 1 m/s
Explanation:
Metric unit conversions:
0.3 km = 300m
5 minutes = 5*60 = 300 seconds
So if a seal can reach a depth of 300m in a time of 300 seconds, its diving speed is the distance divided by time duration
v = s/t = 300/300 = 1m/s
So B is the correct answer
its 13.98. it's simple multiplication 3* 4.66= 13.98
