When the spring is extended by 44.5 cm - 34.0 cm = 10.5 cm = 0.105 m, it exerts a restoring force with magnitude R such that the net force on the mass is
∑ F = R - mg = 0
where mg = weight of the mass = (7.00 kg) g = 68.6 N.
It follows that R = 68.6 N, and by Hooke's law, the spring constant is k such that
k (0.105 m) = 68.6 N ⇒ k = (68.6 N) / (0.105 m) ≈ 653 N/m
the action and reaction do not lead equilibrium if action and reaction force react on different objects
<h3>WATER</h3>
Explanation:
<h2>#CARRYINGTOLEARN:)</h2>
(20 N)/(2 m²) = (20/2) N/m² = 10 Pa
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The pascal (Pa) is the derived SI unit of pressure equal to 1 N/m².
