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Mariulka [41]
3 years ago
9

In a nuclear power plant, _____. energy is released from the nuclei of atoms energy is released from the bonds of molecules ener

gy is released from the electrons of atoms energy is stored in the nucleus of atoms
Physics
2 answers:
oksian1 [2.3K]3 years ago
8 0
In a nuclear power plant, energy is released from the nuclei of atoms. The correct option among all the options given in the question is the first option. Huge amount of thermal energy is released by the breaking of the uranium atoms. This energy is used for turning a turbine that produces electricity. It is a very clean method of producing electricity. 
AleksandrR [38]3 years ago
7 0

Answer: energy is released from the nuclei of atoms

Explanation:

Chemical energy is the energy stored in the bonds of molecules.

Nuclear energy is the energy stored in the nucleus of the atom.

Nuclear power plants use heat produced during nuclear fission to heat water which is produced by the splitting of heavy nucleus into lighter elements by release of energy.

The complete nuclear fission reaction is:

_{92}^{235}\textrm{U}+_0^1\textrm{n}\rightarrow _{56}^{143}Ba+_{36}^{90}Kr+3_0^1\textrm{n}

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If a projectile fired beneath the water, straight up, breaks through the surface at a speed of 13m/s, to what height above the w
OlgaM077 [116]
Well if you had either the velocity or distance traveled i could tell you. But since you haven't all i can say for sure is that the water slowed the bullet down to 13m/s so lets say you knew the distance you would calculate how many meters it traveled and you would have your answer because in this situation, meters (height) =how many seconds spent going into the air. 
3 0
3 years ago
wite a paragraph explaining the difference between things that have matter and things that don't have matter.
mihalych1998 [28]

Answer: Matter is how much space or opacity an object takes up. In short anything that take up space. Things like balls, trees, and even people are all made of matter. Mass is how much matter a object has. Air also has mass also, even though we can't see it. Things like cars, buildings, even planets have mass.

Explanation: Paragraphs are sometimes 4-6 sentences.

6 0
3 years ago
NASA plans to launch a new satellite to orbit the Earth. As the satellite is launched the thrust of the hot exhaust gas is pushe
Leya [2.2K]

Answer:

A    

Explanation:

6 0
3 years ago
Read 2 more answers
1. On each of your equipotential maps, draw some electric field lines with arrow heads indicating the direction of the field. (H
JulijaS [17]

Answer:

The angle between the electric field lines and the equipotential surface is 90 degree.

Explanation:

The equipotential surfaces are the surface on which the electric potential is same. The work done in moving a charge from one point to another on an equipotential surface is always zero.

The electric field lines are always perpendicular to the equipotential surface.

As

dV = \overrightarrow{E} . d\overrightarrow{r}\\\\

For equipotential surface, dV = 0 so

0 = \overrightarrow{E} . d\overrightarrow{r}\\\\

The dot product of two non zero vectors is zero, if they are perpendicular to each other.

5 0
3 years ago
Calculate the translational speed of a cylinder when it reaches the foot of an incline 7.05 mm high. Assume it starts from rest
mestny [16]

Height is 7.05 m and not 7.05 mm

Answer:

9.603 m/s

Explanation:

We are dealing with rotation, so velocity of centre of mass is given by;

v_cm = Rω

Since we are working with a solid cylinder, moment of inertia of the cylinder is; I = ½mR²

Since it is rolled from the top to the bottom, at the top it will have potential energy(mgh) while at the bottom it will have kinetic energy (rotational plus translational kinetic energy).

Using conservation of energy, we have:

P.E = K.E_t + K.E_r

Formula for rotational and kinetic energy here are;

K.E_t = ½mv²

K.E_r = ½Iω²

mgh = ½mv² + ½Iω²

Since we want to find translational speed(v), let's get rid of ω.

Earlier, we saw that v_cm = Rω

Thus; ω = v/R

Also, we know that I = ½mR².

Thus;

mgh = ½mv² + ½(½mR²)(v/R)²

This gives;

mgh = ½mv² + ¼mv²

Divide through by m to get;

gh = v²(½ + ¼)

gh = ¾v²

Making v the subject gives;

v = √(4gh/3)

v = √((4 × 9.81 × 7.05)/3)

v = 9.603 m/s

6 0
3 years ago
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