Given:
rate = k [A]2
concentration is
0.10 moles/liter
rate is 2.7 × 10-5 M*s-1
Required:
Value of k
Solution:
rate = k [A]2
2.7 × 10-5 M*s-1
= k (0.10 moles/liter)^2
k = 2.7 x 10^-3
liter per mole per second
The reaction corresponds to the combustion of propane (C3H8). The balanced reaction is:
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
The reaction enthalpy is given as:
ΔHrxn = ∑nΔH°f(products) - ∑ nΔH°f(reactants)
= [3ΔH°f(CO2(g)) + 4ΔH°f(H2O(g)] - [1ΔH°f(C3H8(g)) + 5ΔH°f(O2(g)]
= [3(-393.5) + 4(-241.8)] - [-103.9 + 5(0)] = -2043.8 kJ
The enthalpy for the combustion of propane is -2044 kJ
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