Answer:
The magnets will push away from each other.
Answer:
Cd(s) + 1/2 O₂(g) ⇒ CdO(s) ΔH° = -258 kJ/mol
Explanation:
The standard heat of formation corresponds to the reaction of synthesis of 1 mole of the desired product from the simple substances in their most stable form under standard conditions (1 bar, 25°C). The resulting thermochemical equation is:
Cd(s) + 1/2 O₂(g) ⇒ CdO(s) ΔH° = -258 kJ/mol
Answer: option C) II < III < I
i.e [OH−] < [H3O+] < I
Explanation:
First, obtain the pH value of I and II, then compare both with III.
For I
Recall that pH = -log (H+)
So pH3O = -log (H3O+)
= - log (1x10−5)
= 4
For II
pOH = - log(OH-)
= - log(1x10−10)
= 9
For III
pH = 6
Since, pH range from 1 to 14, with values below 7 to be acidic, 7 to be neutral, above 7 to be alkaline: then, 9 < 6 < 4
Thus, the following solutions from least acidic to most acidic is II < III < I
The specific heat means the heat absorbed when 1 g of the compound increase 1 ℃. So the specific heat is 41.71/(18.69*17)=0.131 J/(g*k).