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laiz [17]
3 years ago
14

Astronauts in space would not be able to hear a landslide on the moon because

Chemistry
2 answers:
expeople1 [14]3 years ago
8 0

Answer:

there is no sound is space or because there in no gravity

Explanation:

lilavasa [31]3 years ago
5 0

Answer:

there are a couple reasons

they would be able to hear outside there suits i believe also gravity is light on the moon so rocks would likely fall softly where they would notice also landslide would be very rare on the moon due to the material the moon i s made of which would moves do to impact and there are a lot of reasons that anyone could make up

Explanation:

but the scientific answer is : <em>sound waves needs a medium to travel just like our planet, we are able to hear each other because the air around us acts as the medium which sound waves travel, however, the moon does not have any air that sound waves,which a landslide would produce, use to travel from one place to another.</em>

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Please help! ill give medal
weeeeeb [17]
An example of a general formula of an acid is
<span>HCl

This is called as hydrochloric acid or hydrogen chloride.

H represents for the atom of Hydrogen
and Cl represents for the atom of Chlorine

Since their charges are -1, and +1, it's ratio is 1:1</span>
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3 years ago
Genetics and reproduction
Zepler [3.9K]

genetics and reproduction is all about dna.

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2 years ago
2C3H7OH + 9O2 --&gt; 6CO2 + 8H2O
Ne4ueva [31]
<h3>Answer:</h3>

733 g CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced]   2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O

[Given]   5.55 mol C₃H₇OH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol C₃H₇OH → 6 CO₂

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up conversion:                    \displaystyle 5.55 \ mol \ C_3H_7OH(\frac{6 \ mol \ CO_2}{2 \ mol \ C_3H_7OH})(\frac{44.01 \ g \ CO_2}{1 \ mol \ CO_2})
  2. Multiply/Divide:                                                                                               \displaystyle 732.767 \ g \ CO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

732.767 g CO₂ ≈ 733 g CO₂

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A sample of a substance containing only magnesium and chlorine was tested in the lab and was found to be composed of 74.5% chlor
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Use a ratio to find out that x/190.2 = 74.5/100 

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