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Ratling [72]
3 years ago
5

List the main activities of exploration??

Engineering
1 answer:
Trava [24]3 years ago
3 0

Answer:  Exploration includes plethora of activities and depend upon the kind  of exploration a person is doing. But most include some of the basic activities like research , investigation, planning and execution.

Suppose we want to explore new petroleum sites then we would have to start with studying the geography of that area, then according to our research we will analyse the hot spots or the sector where probability of finding of oil field is highest, post that appropriate man power is skilled professionals, tools and machinery will be brought at the site so that execution can take place.

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Calculate the resistance of a circuit with 1.5 A and 120 V. Use the appropriate formula from the list of formulas on the
murzikaleks [220]

Answer:

Option C (80 ohms) is the right answer.

Explanation:

The given values are:

Current,

I = 1.5 A

Voltage,

V = I20 V

As we know,

⇒  V=IR

or,

The resistance will be:

⇒  R=\frac{V}{I}

On substituting the values, we get

⇒      =\frac{120}{1.5}

⇒      =80 \ ohms

5 0
3 years ago
Which process made making copies of technical drawings easier?
kirill115 [55]

Answer:

The Process of printing

Explanation:

hope this helps :)

4 0
2 years ago
You doubled the voltage frequency in an RL series AC circuit, the inductive resistance would?
Ivenika [448]

Answer:

Remain the same.

Explanation:

If you doubled the voltage frequency in an RL series AC circuit, the inductive resistance would <u>remain the same</u>.

6 0
3 years ago
Read 2 more answers
In an experiment, the local heat transfer over a flat plate were correlated in the form of local Nusselt number as expressed by
Stells [14]

Answer:

\dfrac{\bar{h}}{h}=\dfrac{5}{4}

Explanation:

Given that

Nu_x=0.035Re_x^{0.8} Pr^{1/3}

We know that

Rex=ρvx/μ

So

Nu_x=0.035Re_x^{0.8} Pr^{1/3}

Nu_x=0.035\times\left(\dfrac{\rho vx}{\mu}\right)^{0.8}Pr^{1/3}

All other quantities are constant only x is a variable in the above equation .so lets take all other quantities as a constant C

Nu_x=C.x^{0.8}=C.x^{4/5}

We also know that

Nux=hx/K

C.x^{4/5}=\dfrac{hx}{k}

m is the constant

h=mx^{-1/5}

This is local heat transfer coefficient

The average value of h given as

\bar{h}=\dfrac{\int_{0}^{L}hdx}{L}

\bar{h}=\dfrac{5m}{4}\times\dfrac{L^{4/5}}{L}

\bar{h}=\dfrac{5m}{4}L^{-1/5}             ---------1

The value of local heat transfer coefficient at x=L

h=mx^{-1/5}

h=mL^{-1/5}            -----------2

From 1 and 2 we can say that

\dfrac{\bar{h}}{h}=\dfrac{5}{4}

8 0
3 years ago
Who is father of Engineer?
3241004551 [841]

John Smeatom, U.K. 18th century, was the first self-proclaimed, civil engineer in the 18th century and IS considered “the father of modern, civil engineering”.

hoped this helped! :)

4 0
3 years ago
Read 2 more answers
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