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Stels [109]
3 years ago
15

Problem 4: (use energy methods) When s = 0, the spring on the firing mechanism is unstretched. If the spring is pulled back to s

= 100mm and released. The mass of the ball is 0.3kg. Determine: 1. The speed of the ball as it leaves the spring and is about to start moving on the circular track. 2. The maximum angle θ the ball will travel without loosing contact with the circular track. Assume all contact surfaces to be s

Physics
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

Find the attachments for complete solution

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What will occur when the trough of wave A overlaps the trough of wave B?
densk [106]

Constructive interference will occur, which means the waves will combine.

In destructive inference, the waves cancel each other out.

Hope this helps :)

3 0
3 years ago
Read 2 more answers
A block is pulled across a flat surface at a constant speed using a force of 50 newtons at an angle of 60 degrees above the hori
vladimir2022 [97]

The magnitude of the friction force is 25 N

Explanation:

To solve this problem, we just have to analyze the forces acting on the block along the horizontal direction. We have:

  • The horizontal component of the pulling force, F cos \theta, where F = 50 N is the magnitude and \theta=60^{\circ} is the angle between the direction of the force and the horizontal; this force acts in the  forward direction
  • The force of friction, F_f, acting in the backward direction

According to Newton's second law, the net force acting on the block in the horizontal direction must be equal to the product between the mass of the block and its acceleration:

\sum F_x = ma_x

where

m is the mass of the block

a_x is the horizontal acceleration

However, the block is moving at constant speed, so the acceleration is zero:

a_x = 0

So the equation becomes

\sum F_x = 0 (1)

The net force here is given by

\sum F_x = F cos \theta - F_f (2)

And so, by combining (1) and (2), we find the magnitude of the friction force:

F cos \theta - F_f = 0\\F_f = F cos \theta = (50)(cos 60^{\circ})=25 N

Learn more about  force of friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

4 0
3 years ago
11. A bowling ball has a mass of 7 kg and a velocity of 3 m/s.<br> (A) What is the ball's momentum?
DaniilM [7]

Answer: 21 kg x m/s

Momentum can be found using the equation p = mv, or momentum = mass times velocity.

Therefore, to find the momentum of the bowling bowl, you can plug the mass and velocity values into the equation to get p = (7kg)(3m/s)

Solve the equation to get a momentum of 21kg x m/s

I hope I could help :)

7 0
3 years ago
A frictionless spring with a 4-kg mass can be held stretched 0.2 meters beyond its natural length by a force of 30 newtons. If t
maxonik [38]

Answer:

The position for mass is x(t)=36.75sin(37.5t)

Explanation:

Let x(t) donate the position of mass at time t,Then x satisfies the differential equation

m\frac{d^2x}{dt^2} +kx=0\\here\\m=4kg\\k=30N/0.2m\\thus\\w^2=k/m=30N/0.2m*4kg=37.5

The general solution is

(x)t=C_{1}cos(37 .5t)+C_{2}sin(37.5t)

It follows

x'(t)=-37.5C_{1}sin(37.5t)+37.5C_{2}cos(37.5t)\\now\\x(0)=0\\gives\\C_{1}=0\\ and\\x'(0)=1m/s\\gives\\C_{2} =36.75

thus the position of mass is

x(t)=36.75sin(37.5t)

7 0
3 years ago
a beam of electrons passes through an electric field where the magnitude of the electric field strength is 3.00 * 10^3 newtons p
nikdorinn [45]
Electric Field Strength E = Force F/ Charge q

E = F/q

Force , F =   E*q

But charge on an electron q = 1.6 * 10⁻¹⁹ C

E = 3 * 10³ N/C from the question.

Force F =  3* 10³ *   1.6 * 10⁻¹⁹

F = 4.8 * 10⁻¹⁶  N.

Electrostatic force F = 4.8 * 10⁻¹⁶  N
5 0
4 years ago
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