Answer: 68.4 s
Explanation:
The plot points seem to indicate a 5 m/s increase in velocity in the 6 seconds between 2 and 8 second marks. This makes the acceleration
a = 5 / 6 m/s/s
At time zero, the velocity is 13 m/s, so we need to increase by
70 - 13 = 57 m/s
t = v/a = 57 / (5/6) = 68.4 s
Explanation:
It is given that,
Mass of the ball, m = 0.06 kg
Initial speed of the ball, u = 50.4 m/s
Final speed of the ball, v = -37 m/s (As it returns)
(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :
J = -5.24 kg-m/s
(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.
W = -35.1348 Joules
Hence, this is the required solution.
Answer:
yes
Explanation:
when we throw a ball upwards, it will eventually come back to us because of force.
In this question, we know that mass= 10 kg = 10 x 1000 = 10,000 g
Distance = 1 m and Time = 0.5 s
Power = Force x Velocity
Velocity = Distance / Time = 1 m / 0.5 s = 2 m/s
So, Power = Force x (Distance / Time)
But Force= Mass x Acceleration due to gravity (g)
So, Force = 10 kg x 9.8 m/s
= 98
Therefore, Power =Force x Velocity= 98 x 2 =
196 W
Answer:
EMF = 187.5 volts
Explanation:
As per Faraday's law of electromagnetic induction we know that rate of change in the flux will induce EMF
so we can say
now we will have
So the induced EMF in the coil will be 187.5 Volts