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Karo-lina-s [1.5K]
2 years ago
8

DUE BY MIDNIGHT

Physics
1 answer:
olga2289 [7]2 years ago
8 0

Answer:

Option D. 1000 J.

Explanation:

From the question given above, the following data were obtained:

Force (F) applied = 200 N

Distance (s) = 5 m

Time (t) = 10 s

Workdone (Wd) =?

Workdone (Wd) is simply defined as the product of force (F) and distance (s) moved in the direction of the force. Mathematically, it is expressed as:

Wd = F × s

With the above formula, we can calculate the Workdone as illustrated below:

Force (F) applied = 200 N

Distance (s) = 5 m

Workdone (Wd) =?

Wd = F × s

Wd = 200 × 5

Wd = 1000 J

Thus, the Workdone is 1000 J

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Answer:

Multiply the air pressure by the area of the tabletop.

Explanation:

The relationship between pressure, force and area is given by:

p=\frac{F}{A}

where in this case, p is the air pressure, F is the force exerted and A the area of the tabletop. By re-arranging the equation, we can solve for F, the force exerted:

p=\frac{F}{A}\\p\cdot A=\frac{F}{A}\cdot A\\pA=F

So, the correct answer is:

The force exerted on the tabletop can be found by multiplying the air pressure by the area of the tabletop.

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3 years ago
The heating system in Jeff and Tony's new home takes cool air and passes it through the heat source using a fan or blower. What
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<h3>What is heat transfer by convection?</h3>

Convection is the transfer of heat from one place to another due to the movement of fluid.

During heat transfer by convection, cold air replaces hot risen air.

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8 0
1 year ago
How can the atomic number of nitrogen be determined?
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Answer:

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4 0
2 years ago
Define relative density​
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5 0
3 years ago
Consider a large truck carrying a heavy load, such as steel beams. A significant hazard for the driver is that the load may slid
Tanzania [10]

A) 18.4 m

B)

a) mass of the load

b) mass of the truck

Explanation:

A)

In order for the oad not to slide, its acceleration must be the same as the acceleration of the truck.

Since there is only one force acting on the load (the force of static friction), the acceleration of the load will be equal to the force of friction divided by the mass of the load (Newton's second law of motion):

a=\frac{F_f}{m}=\frac{-\mu mg}{m}=-\mu g (1)

where

m is the mass of the load

\mu=0.400 is the coefficient of static friction

g=9.8 m/s^2 is the acceleration due to gravity

The acceleration of the truck (and the load) is also related to the stopping distance of the truck by the suvat equation:

v^2-u^2=2as (2)

where

v = 0 is the final velocity of the car

u = 12.0 m/s is the initial velocity

a is the acceleration

s is the stopping distance

Since the acceleration must be the same, we can substitute (1) into (2), and solving for s we find:

v^2-u^2=-2\mu g s\\s=\frac{v^2-u^2}{-2\mu g}=\frac{0^2-12.0^2}{-2(0.400)(9.8)}=18.4 m

B)

From part A, we see that the data that we have not used in the calculation are:

- The mass of the load

- The mass of the truck

Therefore, the two pieces of data unnecessary for the solution are

a) mass of the load

b) mass of the truck

8 0
3 years ago
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