Answer:
By the information provided we can find the cars speed.
Explanation:
- Speed is the distance traveled by any object in certain time. As we have distance traveled by car as 30 miles.
- And time taken by car to travel 30 miles is half an hour. So speed is easily calculated as,
. - Velocity is a vector quantity so we cannot determine velocity by knowing only distance and time, we need additional information of direction to know cars velocity.
- So the speed will be,
.
Answer : The correct option is, (B)
Explanation :
Electrical energy : It is defined as the movement of the electrons thought the wire.
Chemical energy : It is a type of energy which is stored in the bonds of a chemical compounds. During the chemical reaction, chemical energy is released in the form of heat.
Sound energy : It is a type of energy which is produced when an object vibrate.
Mechanical energy : It is a type of energy that can be used to do work.
The option A is incorrect because in this process, electrical energy being converted to the sound energy.
The option B is correct because in this process, electrical energy being converted to chemical energy. An oxidation-reduction reaction occurs in the storage battery.
The option C is incorrect because in this process, mechanical energy being converted to mechanical energy.
Hence, the option (B) A storage battery is charged using an electric current is an example of electrical energy being converted to chemical energy.
Answer:
3.974 Joule
Explanation:
Diameter of ring = 7.7 cm
a = Distance from the center = d/2 = 3.85 cm = 0.0385 m
Q = Charge = 5 mC
q = Charge to move = 3.4 mC
k = Coulomb constant = 9×10⁹ Nm²/C²
Work done will be equal to Potential energy when mass is at center

∴ Work to move a tiny 3.4 mC charge from very far away to the center of the ring is 3.974 Joule
Slow down before entering the curve. Stay close to the outside. Use the gas pedal as you enter the middle of the curve.
Answer:
a) A = 0.07129 m²
b) A / A ’= 1.77
Explanation:
In this exercise we are asked to find the area in SI units, so let's start by reducing the dimensions to SI units.
width a = 8.5 inch (2.54 cm 1 inch) (1 m / 100 cm)
a = 0.2159 m
length l = 13 inch (2.54 cm / 1 inch) (1 m / 100 cm)
l = 0.3302 m
The area of a rectangle is
A = l a
A = 0.3302 0.2159
A = 0.07129 m²
b) we have a second sheet with reduced dimensions
a ’= 3/4 a
l ’= ¾ l
Let's find the area of this glossy sheet
A ’= l’ a ’
A ’= ¾ l ¾ a
A ’= 9/16 l a
To find the factor we divide the two quantities
A / A ’= l a 16 / (9 l a
A / A ’= 1.77