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JulsSmile [24]
3 years ago
6

Jenny is studying a compound that has two oxygen atoms and one nitrogen atom. Which statement describes the subscripts she will

use to write the chemical formula? She will use one 2 as a subscript. She will use one 2 and one 1 as subscripts. She will use one 3 as a subscript. She will use two 2s and one 1 as subscripts.
Physics
1 answer:
STALIN [3.7K]3 years ago
7 0

Answer:

She will use one 2 as a subscript.

Explanation:

Nitrogen is a chemical element with the symbol "N" and has an atomic number of 7. Thus, it is found in group (5) of the periodic table and as such it has 5 electrons in its outermost shell. Therefore, nitrogen has two (5) valence electrons.

On the other hand, oxygen has an atomic number of 8 and with the symbol "O."

When nitrogen and oxygen react chemically, they produce a compound known as nitrogen dioxide NO_{2}

In this scenario, Jenny is studying a compound that has two oxygen atoms and one nitrogen atom. Therefore, the statement which describes the subscripts she will use to write the chemical formula is, she will use one 2 as a subscript.

N + O_{2} ------>  NO_{2}

Where: 2 represents the subscript of oxygen.

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Answer:

By the information provided we can find the cars speed.

Explanation:

  • Speed is the distance traveled by any object in certain time. As we have distance traveled by car as 30 miles.
  • And time taken by car to travel 30 miles is half an hour. So speed is easily calculated as, Speed = \frac{Distance }{Time }.
  • Velocity is a vector quantity so we cannot determine velocity by knowing only distance and time, we need additional information of direction to know cars velocity.
  • So the speed will be, Speed = \frac{30}{0.5} = 60 miles/hour.
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3 years ago
Which of the following is an example of electrical energy being converted to chemical energy?
tekilochka [14]

Answer : The correct option is, (B)

Explanation :

Electrical energy : It is defined as the movement of the electrons thought the wire.

Chemical energy : It is a type of energy which is stored in the bonds of a chemical compounds. During the chemical reaction, chemical energy is released in the form of heat.

Sound energy : It is a type of energy which is produced when an object vibrate.

Mechanical energy : It is a type of energy that can be used to do work.

The option A is incorrect because in this process, electrical energy being converted to the sound energy.

The option B is correct because in this process, electrical energy being converted to chemical energy. An oxidation-reduction reaction occurs in the storage battery.

The option C is incorrect because in this process, mechanical energy being converted to mechanical energy.

Hence, the option (B) A storage battery is charged using an electric current is an example of electrical energy being converted to chemical energy.

7 0
3 years ago
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A ring of diameter 7.70 cm is fixed in place and carries a charge of 5.00 mC uniformly spread over its circumference. (a) How mu
MatroZZZ [7]

Answer:

3.974 Joule

Explanation:

Diameter of ring = 7.7 cm

a = Distance from the center = d/2 = 3.85 cm = 0.0385 m

Q = Charge = 5 mC

q = Charge to move = 3.4 mC

k = Coulomb constant = 9×10⁹ Nm²/C²

Work done will be equal to Potential energy when mass is at center

U=\frac{kQq}{a}\\\Rightarrow U=\frac{9\times 10^9\times 5\times 10^{-6}\times 3.4\times 10^{-6}}{0.0385}=3.974\ J

∴ Work to move a tiny 3.4 mC charge from very far away to the center of the ring is 3.974 Joule

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3 years ago
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How can a driver best be prepare to enter sharp curves
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Slow down before entering the curve. Stay close to the outside. Use the gas pedal as you enter the middle of the curve.
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3 years ago
(a) A standard sheet of paper measures 8 1/2 by 13 inches. Find the area of one such sheet of paper in m2.8.5(!meter/39.37in) —
Sergeu [11.5K]

Answer:

a)    A = 0.07129 m²

b)    A / A ’= 1.77

Explanation:

In this exercise we are asked to find the area in SI units, so let's start by reducing the dimensions to SI units.

width a = 8.5 inch (2.54 cm 1 inch) (1 m / 100 cm)

            a = 0.2159 m

length l = 13 inch (2.54 cm / 1 inch) (1 m / 100 cm)

              l = 0.3302 m

The area of ​​a rectangle is

            A = l a

             A = 0.3302 0.2159

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b) we have a second sheet with reduced dimensions

         a ’= 3/4 a

         l ’= ¾ l

Let's find the area of ​​this glossy sheet

         A ’= l’ a ’

         A ’= ¾ l ¾ a

         A ’= 9/16 l a

To find the factor we divide the two quantities

           A / A ’= l a 16 / (9 l a

            A / A ’= 1.77

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