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NISA [10]
4 years ago
12

s) A body of mass 2 kilograms moves on a circle of radius 3 meters, making one revolution every 5 seconds. Find the magnitude of

the centripetal force acting on the body. (Be sure to correctly state the units of the force
Physics
1 answer:
jeyben [28]4 years ago
8 0

Answer:

Centripetal force acting on the body = 9.47 N

Explanation:

Mass of body, m = 2 kg

Radius, r = 3 m

It makes one revolution in 5 seconds.

        Period, T = 5 s

        \texttt{Angular velocity, }\omega =\frac{2\pi }{T}=\frac{2\pi }{5}=1.256rad/s

Centripetal force, F = mrω²

                        F = 2 x 3 x 1.256² = 9.47 N

Centripetal force acting on the body = 9.47 N

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D.102m?

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ventriculoperitoneal      

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Problem 4: a long wire carries current towards east. a positive charge moves westward and just north from the wire. what is the
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The direction of the force experienced by the positive charge is upward.

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(if it was a negative charge, we should have taken the opposite direction)
4 0
3 years ago
What is the momentum of a 91- kilogram ice skater gliding across the ice at a speed of 9 m/s
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5 0
3 years ago
Sound travels at a speed of about 344 m/s in air. You see a distant flash of lighting and hear the thunder arrive 7.6 seconds la
Mazyrski [523]

Answer:

0.056 miles away

Explanation:

From sound wave,

v = 2x/t .................................. Equation 1

Where v = velocity of sound in air, x = distance of echo, t = time.

making x the subject of the equation,

x = 2v/t........................... Equation 2.

Given: v = 344 m/s, t = 7.6 s.

Substituting into equation 2

x = 2(344)/7.6

x = 90.53 m.

x = 90.53/1609.344

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Thus the lighting strike 0.056 miles away

8 0
3 years ago
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