Question

During a hockey game, a puck is given an initial speed of 10 m/s. It slides 50 m on the horizontal ice before it stops due to friction. What is the coefficient of kinetic friction between the pick and the ice.A) 0.12B) 0.10C) 0.11D) 0.090

Answer 1

Answer:

The value is  $\mu_k = 0.102$

Explanation:

From the question we are told that

   The initial speed of the pluck is  $u = 10 \ m/s$

    The  distance it slides on the horizontal ice is  $s = 50 \ m$

Generally from kinematic equation we have that

       $v^2 = u^2 + 2as$      

Here v is  is the final velocity and the value is 0 m/s given that the pluck came to rest, so

      $0^2 = 10 ^2 + 2* a * 50$      

=>   $a = - 1 \ m/s^2$

Here the negative sign show that the pluck is decelerating  

 Generally the force applied on the pluck is  equal to the frictional force experienced by the pluck

      So  

                $F = F_f$

=>            $m * a = m* g * \mu_k$

=>             $1 = 9.8 * \mu_k$

=>              $\mu_k = 0.102$