Would any Chemistry braniacs be kind enough to help explain how to work these out? Any help is appreciated, thanks

1. A(n)______________ bond forms when one atom gives up one or more electrons to another atom.

aalyn [17]

1. An____ionic____ bond forms when one atom gives up one or more electrons to another atom.

2. Atoms or molecules with a net electric charge due to the loss or gain of one or more electrons are ions.

3. A_covalent__bond involves the sharing of electron pairs between atoms, also known as a molecular bond. 4. When one pair of electrons is shared between two atoms, a single bond is formed. 5. When two pairs of electrons are shared between two atoms, a double bond is formed. 6. A polar covalent bond is a type of chemical bond where a pair of electrons is unequally shared between two atoms. As a result, one end of the molecule has a slightly negative charge and the other a slightly positive charge. 7. Atoms involved in a nonpolar covalent bond equally share electrons; there is no charge separation to the molecule. 8. A weak bond called a van der waals bond results from an attraction between a slightly positive region in a molecule and a slightly negative region in the same or a different molecule

3 0

4 years ago

A group of students used this diagram to classify three organisms into different kingdoms

lubasha [3.4K]

Don’t click the link I think it a a virus

8 0

3 years ago

How many grams of krypton gas will occupy 2.55 liters at 1.25 atm if it occupies 3.75 liters at 0.750 atm at 255 K

tatiyna

Answer:

There will be 94.7 grams of krypton gas

Explanation:

Step 1: Data given

at 255K and 0.750 atm the volume is 3.75 L

At 1.25 atm the volume is 2.55 L

Molar mass of krypton = 83.798 g/mol

Step 2: Calculate number of moles

p*V = n*R*T

with p = the pressure of the krypton gas = 0.750 atm

with V = the volume of the krypton gas = 3.75 L

with n = the number of moles = TO BE DETERMINED

with R = the gasconstant = 0.08206 L*atm/ mol * K

with T = the temperature = 255 K

n = R*T / p*V

n = (0.08206 * 255)/ (0.750 * 3.75)

n = 0.744 moles

Step 3: Calculate new number of moles

P1*V1 = P2*V2

P1*V1 = n1*R*T

P2*V2 = n2*R*T

(P1*V1)/R*T = (P2*V2)/n2*R*T

Since R and T do not change we can write as followed:

(P1*V1) = (P2*V2) /n2

n2 = (P2*V2) / (P1*V1)

n2 = (2.55 *1.25)/(0.75*3.75)

n2 = 1.13 moles

Step 4: Calculate mass of krypton gas

mass = Number of moles * Molar mass

mass of krypton gas = 1.13 moles * 83.798 g/mol = 94.69 grams ≈ 94.7 grams

There will be 94.7 grams of krypton gas

5 0

3 years ago

What is the molarity of a solution containing 400g cuso4 in 4.00 l of solution

Murrr4er [49]

Calculation-
400gCuSo4
---------------- ] faction 2.5 over 4 which EQUALS .625MCuSO4 in decimal form
1

8 0

4 years ago

Show work plzzz

tekilochka [14]

Answer:

1= Volume

= Length x breath x height

= 13.90 x 2.9 x 0.081

=3.26511

2= Density = Mass ÷ volume

= 11.3 ÷ 3.26511

= 3.461 (3d.p)

idk the rest because you haven't shown a picture of the rest

7 0

3 years ago

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