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AfilCa [17]
3 years ago
15

HELP PLS. WILL GIVE OUT BRAINLIEST!!!

Physics
2 answers:
Afina-wow [57]3 years ago
4 0
Organism

EXPLANATION: I did this
rodikova [14]3 years ago
3 0

Answer:

organism

Explanation:

In the systems

First is

1.cell

group of cells is

2. Tissue

group of tissues

3. Organ

group of organs

4. Organ system

group of organ systems

5.Organism

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if an objects velocity doesn't tell us about the net force on an object, what characteristic of its motion does?
aleksklad [387]
The acceleration of the motion tells us about the net force acting on the body
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3 years ago
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13. How much work does a 35 N force do to lift a potted plant from the floor to a shelf 6 m high?
Nataly_w [17]

Answer:

W= 210 N

Explanation:

Just use work = Fparallel*d

W= 35*6

W= 210 N

8 0
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Which word in the sentence is a gerund?
OleMash [197]
A gerund usually ends wit -ing, so we must find the word that includes that.

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0.250 moles of gas are in a piston.The gas does 109 J of work while 240 J of heat are added. What is the change in internal ener
irina [24]

Answer:

+131Joules

Explanation:

Energy can be expressed using below expresion.

ΔE = (q + w).........eqn(1)

q will be + be if heat is gained hence, q= 240 J

work "w" will be - ve if work is done by the system, hence w= -109 J

Then substitute into eqn(1)

Change in Internal energy=

= (240 -109 )

= +131J

6 0
3 years ago
The de broglie wavelength of an electron with a velocity of 6.00 × 106 m/s is ________ m. The mass of the electron is 9.11 × 10-
WINSTONCH [101]

Answer: 1.212(10)^{-10} m

Explanation:

The de Broglie wavelength \lambda is given by the following formula:

\lambda=\frac{h}{p} (1)

Where:

h=6.626(10)^{-34}\frac{m^{2}kg}{s} is the Planck constant

p is the momentum of the atom, which is given by:

p=m_{e}v (2)

Where:

m_{e}=9.11(10)^{-28}g=9.11(10)^{-31}kg is the mass of the electron

v=6(10)^{6}m/s is the velocity of the electron

This means equation (2) can be written as:

p=(9.11(10)^{-31}kg)(6(10)^{6}m/s) (3)

Substituting (3) in (1):

\lambda=\frac{6.626(10)^{-34}\frac{m^{2}kg}{s}}{(9.11(10)^{-31}kg)(6(10)^{6}m/s)} (4)

Now, we only have to find \lambda:

\lambda=1.2122(10)^{-10} m>>> This is the de Broglie wavelength of the electron

8 0
3 years ago
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