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3 years ago

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Which of these describes the graviational force from a planet

1 answer:

Darina [25.2K]3 years ago

3 0

An who knows

Explanation:

hmmmmm

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A 700-N man jumps out of a window into a fire net 10 m below. The net stretches 2 m before

dangina [55]

Answer:

The maximum potential energy of the net, compared to its unstretched potential energy, is: $E_{mn} -E_{un} = 8400J$

Explanation:

From the question we are told that

The weight of the man is $W_m = 700 \ N$

The distance of the window to the net is $d = 10 \ m$

The distance stretched by net is $D = 2 \ m$

Generally from the of conservation energy , the total energy is conserved

This implies that

$E_m__{i} + E_{un} = E_m__{f}} + E_{mn}$

Where $E_m__{i}}$ is the initial potential energy of the , man which is mathematically evaluated as

$E_m__{i}} = W_m * d$

Substituting values

$E_m__{i}} = 700 *10$

$E_m__{i}} = 7000 \ J$

And $E_{un}$ is the unstretched potential energy of the net

And $E_m__{f}}$ is the final potential energy of the man which is mathematically evaluated as

$E_m__{f}} = - W_m * D$

Substituting values

$E_m__{f}} = - 700 * 2$

$E_m__{f}} = - 1400$

The negative show that the direction of the man is against the direction of gravitational pull

And $E_{mn}$ is the maximum potential energy of the net when stretched

So the above equation becomes

$7000 + E_{un} = - 1400 + E_{mn}$

So

$E_{mn} -E_{un} = 7000 + 1400$

$E_{mn} -E_{un} = 8400J$

7 0

3 years ago

A state in which all of the electrons in an atom have their lowest possible energies.

AnnZ [28]

If an atom<span>, ion, or molecule is at the </span>lowest possible energy<span> level, it and </span>its electrons<span> are said to be in the ground </span>state<span>. If it is at a higher </span>energy<span> level, it is said to be excited, or any </span>electrons<span> that </span>have<span> higher </span>energy<span> than the ground </span>state<span> are excited.</span>

6 0

3 years ago

The air is partially removed at the upper part of the tube and the valve is closed. The height of the water above its pool surfa

torisob [31]

Answer:

2121.2kg/m^3 is the density of the test liquid on the left

Explanation:

See attached file

7 0

3 years ago

One particle has a mass of 3.12 x 10-3 kg and a charge of +8.8 C. A second particle has a mass of 7.1 x 10-3 kg and the same cha

never [62]

Answer: $r_i=0.016119\ m\approx 16.119\ mm$

Explanation:

Given

mass of first particle is $m_1=3.12\times 10^{-3}\ kg$

mass of second particle is $m_2=7.1\times 10^{-3}\ kg$

Charge on both the particle $q=8.8\times 10^{-6}\ C$

Now final speed of first particle is $v_1=131\ m/s$

Final separation between particles is $r=0.15\ m$

As there is no external force therefore linear momentum is conserved

$0+0=m_1v_1+m_2v_2$

$0=3.12\times 10^{-3}\times 131+7.1\times 10^{-3}\times v_2$

$v_2=-\dfrac{3.12\times 10^{-3}}{7.1\times 10^{-3}}\times 131$

$v_2=-57.56\ m/s$

Conserving total energy

Initial Kinetic energy +Initial Potential energy=Final Kinetic energy +Final Potential energy

$\Rightarrow 0+\frac{kq^2}{r_i}=\frac{1}{2}m_1v_1^2+\frac{1}{2}m_2v_2^2+\frac{kq^2}{r_f}$

$\Rightarrow \frac{9\times 10^9\times 8.8^2\times 10^{-12}}{r_i}=\frac{1}{2}\times 3.12\times 10^{-3}\times 131^2+\frac{1}{2}7.1\times 10^{-3}\times (57.56)^2+\frac{9\times 10^9\times 8.8^2\times 10^{-12}}{0.15}$

$\Rightarrow \frac{0.696}{r_i}=26.771+11.76+4.646$

$\Rightarrow \frac{0.696}{r_i}=43.177$

$r_i=0.016119\ m\approx 16.119\ mm$

7 0

3 years ago

Two cars are moving. The first car has twice the mass of the second car but only half as much kinetic energy. When both cars inc

Zanzabum

Answer:

20 mi

Exp3tanation:

I did the same question in a quizz

8 0

3 years ago