8.0 m/s if there is no air resistance. (B)
Less if there IS any air resistance.
Answer:
The Position of the object L = 0.172 m
Explanation:
The detailed explanation of the question is given in the attach document.
Answer:
686.11 N
1.7733 gallons
Explanation:
= Efficiency = 30%
V = Volume of gasoline
E = Energy content of gasoline = 
F = Force
s = Displacement = 108000 m
v = Velocity
Work done is given by
The force required to keep the car moving at a constant speed is 686.11 N
Here the force is directly proportional to speed
The gallons that will be used is 1.7733 gallons
Answer: Ok, so you know the acceleration, lets call it A.
now, the velocity will take the form of V= A*t + v0, where v0 is the inicial velocity, in this case the boat starts from the rest, so v0 = 0
integrating again you obtain R = (A*t*t)/2 + r0, and we will take r0 = 0.
so, at a time t₁ we have a velocity V = v = A*t₁
R = r = (A*t₁*t₁)/2
so a t₂=2*t₁
V= A*2*t₁= 2v
R= 0.5*A*t₁*t₁*4 = 4r
so the answer is c.
Answer:
ΔK.E = 2.5 × 10⁻³ J
Explanation:
Given data in the question, we have:
Charge of the particle, q = 5.0 μC = 5 × 10 ⁻⁶ C
Initial speed of the particle, v = 55 m/s
The potential difference, ΔV = 500 V
Now, the gain in kinetic energy is given as
ΔK.E = q × ΔV
on substituting the values in the above formula, we get
ΔK.E = 5 × 10 ⁻⁶ C × 500 V
or
ΔK.E = 2.5 × 10⁻³ J
