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Alex17521 [72]
3 years ago
5

Which solid-state component can be used as a switch to turn current on or off?

Physics
2 answers:
geniusboy [140]3 years ago
7 0

Answer:

Transistor

Explanation:

Papessa [141]3 years ago
4 0
The answer is Transistor. Its a semiconductor device used to amplify or switch electronic signals and electrical power. It is composed of semiconductor material usually with at least three terminals for connection to an external circuit.
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Why is it expensive to bring electricity into urban areas?
motikmotik
Because of the pole and the generator you would have to biuld
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3 years ago
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Kepler’s third law can be used to derive the relation between the orbital period, P (measured in days), and the semimajor axis,
NikAS [45]
Kepler's 3rd law is given as
P² = kA³
where
P = period, days
A = semimajor axis, AU
k = constant

Given:
P = 687 days
A = 1.52 AU

Therefore
k = P²/A³ = 687²/1.52³ = 1.3439 x 10⁵ days²/AU³

Answer:  1.3439 x 10⁵ (days²/AU³)

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3 years ago
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A machine is designed to fill jars with 16 ounces of coffee. A consumer suspects that the machine is not filling the jars comple
babunello [35]

Answer:

a) Null hypothesis:  \mu \geq 16  

Alternative hypothesis :\mu  

b) t=\frac{15.6-16}{\frac{0.3}{\sqrt{8}}}=-3.77  

p_v =P(t_{(7)}  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

c) We can conclude that the mean is significantly less than 16 ounces at 10% of significance.  so then the consumer suspect is correct.

Explanation:

Data given and notation  

\bar X=15.6 represent the mean for the sample

s=0.3 represent the sample standard deviation  

n=8 sample size  

\mu_o =16 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

Is a one tailed left test.  

What are H0 and Ha for this study?  

Null hypothesis:  \mu \geq 16  

Alternative hypothesis :\mu  

The degrees of freedom on this case are:

df=n-1=8-1=7

Compute the test statistic

The statistic for this case is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{15.6-16}{\frac{0.3}{\sqrt{8}}}=-3.77  

Give the appropriate conclusion for the test

Since is a one side left tailed test the p value would be:  

p_v =P(t_{(7)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

We can conclude that the mean is significantly less than 16 ounces at 10% of significance.  so then the consumer suspect is correct.

3 0
3 years ago
Which of the following accurately describes the differences between the SI and English systems of measurement?
Digiron [165]
The best answer is D. The SI system, which is based on the metric system, has been more widely adopted than the English system, which is harder to use. In order to standardize measurements, the International System of Units or the SI units are commonly used around the world since they are more easy to understand and compare than the English unit.
4 0
3 years ago
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A pipe open at both ends has a fundamental frequency of 220 Hz when the temperature is 0°C. (a) What is the length of the pipe?
Allushta [10]

Explanation:

It is given that,

Fundamental frequency, f = 220 Hz

(a) We know that at 0 degrees, the speed of sound in air is 331 m/s.

For open pipe, \lambda=2l

l is the length of pipe

Also,

v=f\lambda

l=\dfrac{v}{2f}=\dfrac{331}{2\times 220}=0.75\ m

(b) Let f' is the fundamental frequency of the pipe at 30 degrees and v' is its speed.

v'=331\sqrt{1+\dfrac{T}{273}}

v'=331\sqrt{1+\dfrac{30}{273}}

v' = 348.71 m/s

So, f'=\dfrac{v'}{\lambda}

f'=\dfrac{348.71}{2\times 0.75}

f' = 232.4 Hz

Hence, this is the required solution.

8 0
3 years ago
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