Answer:
zero velocity
Explanation:
if the v-t graph is parallel to the time axis its mean body has covered no path in other words the body is at rest so the velocity of the body should be zero
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The law of conservation energy
PE₁ + KE₁ = PE₂ + KE₂
From rest ⇒ v₁ = 0 ⇒ KE₁ = 0
Input the value:
PE₁ = PE₂ + KE₂
Answer:
Power = 14.7 W
Explanation:
Given:
Mass of the object to be raised is,
Height to be raised is,
Time taken during the work is,
As the object is raised vertically, the acceleration acting on it is due to gravity and is equal to 9.8 m/s².
Now, work done in moving an object of mass 'm' to a height 'h' is given as:
Now, power is given as the rate of doing work which is given as:
Now, plug in all the values and solve for power. This gives,
Therefore, the power required to raise the object to a height of 3 meters is 14.7 watts.
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Heat = mass CH3OH x spht CH3OH x delta T
<span>= (50 g)(2.51 J/g K)(40 K) = 5020 J </span>
<span>Note that delta T is the same for K as for C.</span>
Answer:
Is your question asking for the muzzle velocity of the bullet?
Explanation:
I will assume it does
The bullet travels horizontally to the target in the same amount of time it falls 2.3 cm from vertical rest
s = ½at²
t = √(2s/g) = √(2(0.023) / 9.8) = 0.0685118...s
v = d/t = 47/0.0685118 = 686.01242...
v = 690 m/s