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GarryVolchara [31]
3 years ago
12

One object is thrown vertically upward with an initial velocity of 100 m/s and

Physics
1 answer:
gavmur [86]3 years ago
8 0

We have that for the Question it can be said that The maximum height reached  by the first <em>object</em> will be  100 times  that of the other.

  • (H_{max})_1=100*(H_{max})_2

From the question we are told

One object is thrown vertically upward with an initial velocity of 100 m/s and  another object with an initial velocity of 10 m/s. The maximum height reached  by the first object will be

that of the other.

a. 10,000 times

b. none of these

<em>c. </em><em>1000 times</em>

d. 100 times

<em>e.</em><em> 10 times</em>

Generally the equation for the velocity is mathematically given as

v=\frac{d}{t}\\\\Where\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{(V_1)^2}{(v_2)^2}\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{10000}{(10}\\\\

(H_{max})_1=100*(H_{max})_2

Therefore

The maximum height reached  by the first <em>object</em> will be  100 times  that of the other.

(H_{max})_1=100*(H_{max})_2

For more information on this visit

brainly.com/question/23379286

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