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3 years ago

When salt dissolves in water, the water molecules are attracted by dissolves salt particles. This attraction is called ?

1 answer:

4 0

When salt dissolves in water, the water molecules are attracted by dissolves salt particles. This attraction is called dissociation.

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Which material property is most directly related to the x-axis value at the x-intercept of the interatomic force versus distance

Brrunno [24]

Answer:

Explanation:

The mechanical properties of a material affect how it behaves as it is loaded. The elastic modulus of the material affects how much it deflects under a load, and the strength of the material determines the stresses that it can withstand before it fails

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2 years ago

Why is each year's vaccine different?

Degger [83]

Because the birds that fly overseas carry different flu viruses every year.

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3 years ago

Read 2 more answers

Partner Namets) For each of the following reactions carried out: Write the balanced chemical equation, the full ionic equation,

torisob [31]

Answer : The full balanced ionic equation will be,

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)$

Reactants are lead nitrate and potassium iodide.

Products are lead iodide and potassium nitrate.

The spectator ions are, $K^+,NO_3^-$

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When potassium iodide react with lead nitrate then it gives potassium nitrate and lead iodide as a product.

The full balanced ionic equation will be,

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)$

The ionic equation in separated aqueous solution will be,

$2K^+(aq)+2I^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow PbI_2(s)+2K^+(aq)+2NO_3^{-}(aq)$

In this equation, $K^+\text{ and }NO_3^-$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Pb^{2+}(aq)+2I^{-}(aq)\rightarrow PbI_2(s)$

4 0

4 years ago

How many photons are produced in a laser pulse of 0.364 J at 477 nm?

Luda [366]

Answer:

1.00 × 10¹⁸

Explanation:

1. Calculate the energy of one photon

The formula for the energy of a photon is

E = hc/λ

h = 6.626 × 10⁻³⁴ J·s; c = 2.998 × 10⁸ m·s⁻¹

λ = 477 nm = 477 × 10⁻⁹ m Insert the values

E = (6.626 × 10⁻³⁴ × 2.998× 10⁸)/(477 × 10⁻⁹)

E = 4.165× 10⁻¹⁹ J

2. Calculate the number of photons

Divide the total energy by the energy of one photon.

No. of photons = 0.418 × 1/4.165 × 10⁻¹⁹

No. of photons = 1.00 × 10¹⁸

7 0

3 years ago

HELP PLZ!!!!!

Molodets [167]

The answer would be c as the cart is not in motion therefor ruling out kinetic and it is completely at rest making all of it energy potential

6 0

3 years ago