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notsponge [240]
3 years ago
8

You are assembling cars, and your job is to put the wheels on the vehicles. You have 3520 wheels, 14040 nuts (4 nuts needed per

wheel) and 1000 car bodies at the start of the day (you have time to do more than 1000, and there will be no deliveries of additional parts during the day).
How many possible cars can roll off the assembly line?
What is the limiting reagent in this case?
If you only get to put the wheels on 850 cars that day, what is your productivity?
Chemistry
1 answer:
amm18123 years ago
4 0
14040/4=3510 wheels per 4 nuts
3510/4=877.5 cars per 4 wheels
877 possible cars.

actual yield 850/theortical yield 877=96.92%
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vova2212 [387]

Answer:

1.4 g/cm3

Explanation:

Density = Mass/Volume

Mass = 21g

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Density = 21/15 = 1.4

8 0
2 years ago
You wish to construct a buffer of pH=7.0. Which of the following weak acids (w/ corresponding conjugate base) would you select?
Alex17521 [72]

Answer:

C.) HOCl Ka=3.5x10^-8

Explanation:

In order to a construct a buffer of pH= 7.0 we need to find the pKa values of all the acids given below

we Know that

pKa= -log(Ka)

therefore

A) pKa of  HClO2 = -log(1.2 x 10^-2)

=1.9208

B) similarly PKa of HF= -log(7.2 x 1 0^-4)= 2.7644

C)  pKa of HOCl= -log(3.5 x 1 0^-8)= 7.45

D) pKa of HCN = -log(4 x 1 0^-10)=  9.3979

If we consider the  Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution

The weak acid for making the buffer must have a pKa value near to the desired pH of the weak acid.

So, near to value, pH=7.0. , the only option is HOCl whose pKa value is 7.45.

Hence, HOCl will be chosen for buffer construction.

3 0
3 years ago
I need help with my homework.Calculate the number of formula units in: 41.5 grams CaBr2
lana66690 [7]

Answer:

\text{ }1.25\times10^{23}\text{ formula units}

Explanation:

Here, we want to calculate the number of formula units in the given molecule

We start by getting the number of moles

To get the number of moles, we have to divide the mass given by the molar mass

The molar mass is the mass per mole

The molar mass of calcium bromide is 200 g/mol

Thus, we have the number of moles as follows:

\frac{41.5}{200}\text{ = 0.2075 mol}

The number of formula units in a mole is:

1\text{ mole = 6.02 }\times10^{22}\text{ formula units}

The number of formula units in 0.2075 mole will be:

0.2075\text{ }\times6.02\times10^{23}\text{ = }1.25\times10^{23}\text{ formula units}

5 0
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sveta [45]

Answer:homogeneous mixture

A sandstorm is a homogeneous mixture.

Explanation:

6 0
2 years ago
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