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notsponge [240]
3 years ago
8

You are assembling cars, and your job is to put the wheels on the vehicles. You have 3520 wheels, 14040 nuts (4 nuts needed per

wheel) and 1000 car bodies at the start of the day (you have time to do more than 1000, and there will be no deliveries of additional parts during the day).
How many possible cars can roll off the assembly line?
What is the limiting reagent in this case?
If you only get to put the wheels on 850 cars that day, what is your productivity?
Chemistry
1 answer:
amm18123 years ago
4 0
14040/4=3510 wheels per 4 nuts
3510/4=877.5 cars per 4 wheels
877 possible cars.

actual yield 850/theortical yield 877=96.92%
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First, find the volume the solution needs to be diluted to in order to have the desired molarity:
You have to use the equation M₁V₁=M₂V₂ when ever dealing with dilutions.

M₁=the starting concentration of the solution (in this case 2.6M)
V₁=the starting volume of the solution (in this case 0.035L)
M₂=the concentration we want to dilute to (in this case 1.2M)
V₂=the volume of solution needed for the dilution (not given)

Explaining the reasoning behind the above equation:
MV=moles of solute (in this case KCl) because molarity is the moles of solute per Liter of solution so by multiplying the molarity by the volume you are left with the moles of solute.  The moles of solute is a constant since by adding solvent (in this case water) the amount of solute does not change.  That means that M₁V₁=moles of solute=M₂V₂ and that relationship will always be true in any dilution.

Solving for the above equation:
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 Second, Finding the amount of water needed to be added:
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I hope this helps.  Let me know if anything is unclear.
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