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3 years ago

What are some constraints related to size, time, or materials? Remember, constraints are limitations, issues, or obstacles.

Engineering

1 answer:

Sergeeva-Olga [200]3 years ago

4 0

Answer:

too big, too small, deadlines, not enough materials

Explanation:

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Identify the unit of the electrical parameters represented by L and C and prove that the resonant frequency (fr)=1÷2π√LC

Gre4nikov [31]

Answer:

L = Henry

C = Farad

Explanation:

The electrical parameter represented as L is the inductance whose unit is Henry(H).

The electrical parameter represented as C is the inductance whose unit is Farad

Resonance frequency occurs when the applied period force is equal to the natural frequency of the system upon which the force acts :

To obtain :

At resonance, Inductive reactance = capacitive reactance

Equate the inductive and capacitive reactance

Inductive reactance(Xl) = 2πFL

Capacitive Reactance(Xc) = 1/2πFC

Inductive reactance(Xl) = Capacitive Reactance(Xc)

2πFL = 1/2πFC

Multiplying both sides by F

F * 2πFL = F * 1/2πFC

2πF²L = 1/2πC

Isolating F²

F² = 1/2πC2πL

F² = 1/4π²LC

Take the square root of both sides to make F the subject

F = √1 / √4π²LC

F = 1 /2π√LC

Hence, the proof.

8 0

3 years ago

We know that passengers can be either helpful or harmful to a driver. Describe a pro and a con of having passengers in your car.

anygoal [31]

Answer:

sub to pewdipie

6 0

3 years ago

Read 2 more answers

If the feedforward path of a control system contains at least one integrating element, then the output continues to change as lo

Thepotemich [5.8K]

Answer:

The attached system shows that there’s an integrator between the point where disturbance enters the system and error measuring element. A any time when R(s)=0 then

$\frac {C(s)}{D(s)}=\frac {G(s)}{1+G_c(s)G(s)}$ and considering that $E(s)=D(s)-G_c(s)C(s)$ then

$\frac {E(s)}{D(s)}=1-(\frac {C(s)}{D(s)})G_c(s)$

$\frac {E(s)}{D(s)}=1-(\frac {G(s)}{1+G_c(s)D(s)})G_c(s)$

$\frac {E(s)}{D(s)}=\frac {1}{1+G_c(s)G(s)}$

$E(s)=\frac {D(s)}{1+G_c(s)G(s)}$

For ramp disturbance d(t)=at

$D(s)=\frac {a}{s^{2}}$ therefore, the steady state error is given by

$e(\infty)= \lim_{s \to 0} s E(s)$

$e(\infty)= \lim_{s \to 0} s [\frac {D(s)}{1+G_c(s)G(s)}]$

$e(\infty)= \lim_{s \to 0} s [\frac {a}{s^{2}+s^{2}G_c(s)G(s)}]$

$e(\infty)= \lim_{s \to 0} s [\frac {a}{s+sG_c(s)G(s)}]$

$e(\infty)= \lim_{s \to 0} s [\frac {a}{sG_c(s)G(s)}]$

Whenever $G_c(s)$ has a double intergrator, the error $e(\infty)$ becomes zero

3 0

3 years ago

The force exerted on a vane due to a jet of water is only a function of the mass flowrate and independent of the jet velocity. a

hoa [83]

Answer:

b) false

Explanation:

We know that rate of change of momentum is called force.

Force = rate of change of momentum

$F=\dfrac{dP}{dt}$

We know that

P = m v

$\dfrac{dP}{dt}=\dfrac{dm}{dt}V$ (take velocity in constant and not changing with time)

$F=\dfrac{dm}{dt}V$

So $F=\dot{m}V$

So force exerted by jet depends on mass flow rate and velocity also.So our option b is right.

5 0

3 years ago

There are three homes being built, each with an identical deck on the back. Each deck is comprised of two separate areas. One ar

9966 [12]

9514 1404 393

Answer:

746.7 ft²

Explanation:

You can add them up, or you can take advantage of multiplication to make the repeated addition simpler.

(112.5 ft² +136.4 ft²) +(112.5 ft² +136.4 ft²) +(112.5 ft² +136.4 ft²)

= (3)((112.5 ft² +136.4 ft²) = 3(248.9 ft²) = 746.7 ft²

The total area of the decks on the 3 homes is 746.7 ft².

7 0

3 years ago