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Gala2k [10]
3 years ago
5

A motor vehicle has a mass of 1200kg and the road wheels have a radius of 360mm. The engine rotating parts have a moment of iner

tia of 0.36kgm2 and the four wheels together have a moment of inertia of 4.8kgm2. The gear ratio from engine to back axle is 6 and when the vehicle speed is v m/s, the engine torque available for propulsion is 82Nm and the resistance to motion is (240 +0?)N. Determine the acceleration of the vehicle at a speed of 15m/s on a level road and the time required to increase the speed of the vehicle from 15 to 25m/s​
Engineering
1 answer:
mihalych1998 [28]3 years ago
6 0

Answer:

manda a senha do brainly bloquearam os amigos e você vai ver o meu perfil completo a minha amiga Jeciane estamos fazendo uma academia de lima e você vai ver o meu perfil completo a minha amiga Jeciane estamos completo a minha amiga Jeciane estamos fazendo uma academia de lima e você vai ver o meu perfil você vai ver o meu perfil você vai ver o meu perfil completo a minha amiga Jeciane estamos fazendo uma academia de lima e fazendo uma academia de lima e fazendo uma academia de lima e fazendo uma academia de lima e fazendo uma academia de lima e fazendo uma academia de lima e você vai ver o meu perfil completo a minha amiga Jeciane estamos fazendo

Explanation:

Marcar como melhor porfavo

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Write the chemical equation of the polymerization reaction to synthesize PS
marin [14]

Explanation:

Styrene is  a vinyl monomer in which there is a carbon carbon double bond.

The polymerization of the styrene, which is initiated by using a free radical which reacts with the styrene and the compound thus forms react again and again to form polystyrene (PS).

The equation is shown below as:

\begin{matrix}& C_6H_5 \\&|\\n H_2C & =CH\end{matrix}        ⇒                \begin{matrix}&C_6H_5 \\&|\\ -[-H_2C & -CH-]-_n\end{matrix}

6 0
3 years ago
You can help build a safe work environment by using your knowledge of violence prevention strategies to spot what?
Ostrovityanka [42]

Answer:

warning signs

Explanation:

give directions on your surroundings

4 0
3 years ago
As project manager, you approve a team member’s request to change the order of their tasks because they think it will be more ef
Oduvanchick [21]

The project is going to scope if the situation happens. Option A is correct.

<h3 /><h3>What is the function of a project manager?</h3>

Project managers are in charge of organizing, planning, and guiding the execution of certain projects for an organization .

As the project manager, you grant a team member's request to rearrange their work in a way they believe will increase productivity.

However, this modification interferes with another team member's workflow since they now have to complete two more activities that are unrelated to the project's objective. The project will be within its scope.

Hence option A is correct.

To learn more about the project manager refer;

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6 0
2 years ago
Suppose that you can throw a projectile at a large enough v0 so that it can hit a target a distance R downrange. Given that you
viktelen [127]

Answer:

\theta_1=15^o\\\theta_2=75^o

Explanation:

<u>Projectile Motion</u>

In projectile motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration (assuming no friction), and the acceleration in the vertical direction is always the acceleration of gravity. The basic formulas are shown below:

V_x=V_{ox}=V_ocos\theta

Where \theta is the angle of launch respect to the positive horizontal direction and Vo is the initial speed.

V_y=V_{oy}-gt=V_osin\theta-gt

The  horizontal and vertical distances are, respectively:

x=V_{o}cos\theta t

\displaystyle y=y_o+V_{o}sin\theta t-\frac{gt^2}{2}

The total flight time can be found as that when y = 0, i.e. when the object comes back to ground (or launch) level. From the above equation we find

\displaystyle t_f=\frac{2V_osin\theta}{g}

Using this time in the horizontal distance, we find the Range or maximum horizontal distance:

\displaystyle R=\frac{V_o^2sin2\theta}{g}

Let's solve for \theta

\displaystyle sin2\theta=\frac{R.g}{V_o^2}

This is the general expression to determine the angles at which the projectile can be launched to hit the target. Recall the angle can have to values for fixed positive values of its sine:

\displaystyle \theta_1=\frac{asin\left(\frac{R.g}{V_o^2}\right)}{2}

\displaystyle \theta_2=\frac{180^o-asin\left(\frac{R.g}{V_o^2}\right)}{2}

Or equivalently:

\theta_2=90^o-\theta_1

Given Vo=37 m/s and R=70 m

\displaystyle \theta_1=\frac{asin\left(\frac{70\times 9.8}{37^2}\right)}{2}

\theta_1=15^o

And

\theta_2=90^o-15^o=75^o

5 0
3 years ago
The mechanical properties of a metal may be improved by incorporating fine particles of its oxide. Given that the moduli of elas
mojhsa [17]

Answer:

A) Upper bound modulus of elasticity; E = 165.6 GPa

B) Lower bound modulus of elasticity; E = 83.09 GPa

Explanation:

A) Formula for upper bound modulus is given as;

E = E_m(1 - V_f) + E_f•V_f

We are given;

E_m = 60 GPa

E_f = 380 GPa

V_f = 33% = 0.33

Thus,

E = 60(1 - 0.33) + 380(0.33)

E = (60 x 0.67) + 125.4

E = 165.6 GPa

B) Formula for lower bound modulus is given as;

E = 1/[(V_f/E_f) + ((1 – V_f)/E_m)]

E = 1/[(0.33/380) + ((1 – 0.33)/60)]

E = 1/(0.0008684 + 0.01116667)

E = 1/0.01203507

E = 83.09 GPa

3 0
3 years ago
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