Answer : The mass of vanadium(V) oxide will be 
Explanation : Given,
Number of atoms of 
= 
Molar mass of = 181.88 g/mole
In , there are 2 atoms of vanadium and 5 atoms of oxygen.
First we have to determine the moles of .
As, 
number of vanadium atom present in 1 moles of
So, number of vanadium atom present in 
moles of
Now we have to determine the mass of .
Therefore, the mass of vanadium(V) oxide will be
The given question is incomplete, the complete question is:
A reaction between liquid reactants takes place at 10.0 °c in a sealed, evacuated vessel with a measured volume of 35.0 L. Measurements show that the reaction produced 28. g of dinitrogen difluoride gas. Calculate the pressure of dinitrogen difluoride gas in the reaction vessel after the reaction. You may ignore the volume of the liquid reactants. Round your answer to 2 significant digits. pressure:atm
Answer:
The correct answer is 0.28 atm.
Explanation:
The temperature mentioned in the given reaction is 10 degree C, which after conversion becomes 283 Kelvin (273+10 = 283K).
The volume mentioned in the reaction is 35 Liters.
The reaction produced 28 grams of dinitrogen difluoride gas (N2F2). The n or the no of moles of the gas can be determined with the help of the formula:
moles of N2F2 = mass/molar mass
= 28/66 (molar mass of N2F2 is 66 g/mol)
= 0.424
The pressure of the gas can be determined by using the equation of the ideal gas law, that is, PV = nRT
P * 35 = 0.424 * 0.0821 * 283
P = 0.28 atm
Answer:
a. the solution is a base
Explanation:
The pH range is between 0 to 14.
A solution with a pH value between 0 and 6 is said to be acidic.
A solution with pH value at 7, is said to be neutral, e.g., distilled water.
A solution with pH value between 8 and 14 is a base.
Given pH = 10, a pH value of 10 falls between the base or alkali range of the indicator
<u>Answer and Explanation:</u>
Mercury combines with sulfur as follows -
Hg + S = HgS
Hg = 200,59
S = 32,066 Therefore 1.58 g of Hg will react with -
1.58 multiply with 32,066 divide by 200,96 of sulfur.
= 0.25211 g S
This will form 1.58 + 0.25211 g HgS = 1.83211 g HgS
The amount of S remaining = 1.10 - 0.25211 = 0.84789 g
Explanation:
https://socratic.org/questions/using-the-equation-2-h2-o2-2-h2o-determine-how-many-grams-of-oxygen-will-be-need
