1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SOVA2 [1]
3 years ago
12

Someone help please????

Chemistry
2 answers:
Mandarinka [93]3 years ago
7 0

Answer:

A is the answer

Explanation:

Dafna1 [17]3 years ago
4 0

Answer:

A

Explanation:

Your answer is A

You might be interested in
Mendeleev used his periodic table of elements to
pishuonlain [190]
<span>Mendeleev realized that the physical and chemical properties of elements were related to their atomic mass in a 'periodic' way, and arranged them so that groups of elements with similar properties fell into vertical columns in his table.
</span>Mendeleev rewrote each edition of Principles of Chemistry<span>, including all new scientific data-particularly confirmations of the periodic law-and reanalyzing difficulties that had arisen to hinder its confirmation (inert gases, radioactivity, radioactive and </span>rare-earth elements<span>)
</span>he wanted to prove that he was right.
7 0
2 years ago
A 1.42-g sample of a pure compound with formula m2so4 was dissolved in water and treated with an ex- cess of aqueous calcium chl
solong [7]

The reaction between m_{2}SO_{4} with calcium chloride can be shown as-m_{2}SO_{4}+CaCl_{2}→CaSO_{4}↓+2mCl. The molecular weight of CaSO_{4} is 136.14g. The weight of sulfate ion is 96.06g. The molecular weight of m_{2}SO_{4} = (2×m + 96.06). From the reaction we can see that 1 mole of calcium chloride reacts with 1 molesm_{2}SO_{4} to produce 1 mole of calcium sulfate. Now 1.36g of calcium sulfate is equivalent to 1.36/136.14=9.989×10^{-3} moles of calcium sulfate.

Thus, 9.989×10^{-3} moles of m_{2}SO_{4} reacts in this reaction.

Let assume the atomic mass of m is x thus the molecular weight of m_{2}SO_{4} is 2x+96.

So we may write 9.989×10^{-3}× (2x+96) =1.42

Or, 2x + 96 = 142.146

Or, 2x = 46.146

Or, x = 23.073

Thus the atomic mass of m is 23.073. The atom (m) is sodium (Na).  

8 0
3 years ago
∆G° for the process benzene (l) benzene (g) is 3.7 Kj/mol at 60 °C , calculate the vapor pressure of benzene at 60 °C [R=0.0821
Alex787 [66]

Answer:

4) 0.26 atm

Explanation:

In the process:

Benzene(l) → Benzene(g)

ΔG° for this process is:

ΔG° = -RT ln Q

<em>Where Q = P(Benzene(g)) / P°benzene(l) P° = 1atm</em>

ΔG° = 3700J/mol = -8.314J/molK * (60°C + 273.15) ln P(benzene) / 1atm

1.336 = ln P(benzene) / 1atm

0.26atm = P(benzene)

Right answer is:

<h3>4) 0.26 atm </h3><h3 />
6 0
2 years ago
hat is the product when magnesium reacts with nitrogen? Mg(s) + N2(g) → Mg2N3(s) Mg3N(s) Mg3N2(s) MgN3(s)
Ipatiy [6.2K]
3Mg + N₂ = Mg₃N₂

Mg₃N₂
______________________
5 0
3 years ago
Read 2 more answers
What tool does the US government use to keep track of inflation throughout the years?
Alchen [17]
The answer is d the inflation scale
3 0
3 years ago
Read 2 more answers
Other questions:
  • The equilibrium constant of a reaction: A) is not related to the change in free energy of the reaction. B) is the same as the ma
    10·1 answer
  • Where are non-metals located on the periodic table on the right of the periodic table after the staircase where would you find t
    8·1 answer
  • If 4.04 g of N combine with 11.46 g O to produce a compound with a formula mass of 108.0 amu, what isn’t the molecular formula o
    9·1 answer
  • Find the Ka of nitrous acid given that a 0.20 M solution of the acid has a hydrogen ion concentration of 2.8*10-3 M. HNO2 (aq) ?
    14·1 answer
  • The electron configuration of vanadium (III)ion is:
    11·2 answers
  • When a substance undergoes a Chemical Change, can the change be reversed? Explain your answer.​
    8·2 answers
  • What are the 10 metals?​
    6·1 answer
  • Helpppppppppppppppppp​
    10·2 answers
  • H:C::C:H<br> is the following molecule polar or nonpolar
    15·1 answer
  • a student carried out a combustion reaction with methane (ch4) as the limiting reagent. a 12.0g quantity of methane was used, an
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!