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iris [78.8K]
2 years ago
10

Please help as soon and best answer gets brainlest

Chemistry
1 answer:
Ann [662]2 years ago
5 0

Answer:

Mass, temperature, and phase.

I think temperature because the higher the temperature of a given quantity of a substance, more is its thermal energy. Similarly, for the same temperature, higher mass of a substance will contain more thermal energy.

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In a metal what is not given an assigned location and thus can drift
Allushta [10]
In a metal, "Electrons" <span> is not given an assigned location and thus can drift

In short, Your Answer would be Option C

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6 0
2 years ago
Use the molar heat capacity for aluminum from table 1 to calculate the amount of energy needed to raise the temperature of 260.5
Nimfa-mama [501]
Unfortunately, you failed to include the table 1 from which the molar heat capacity of aluminum could have been obtained. However, as a general rule, the heat needed to raise the temperature of a certain substance by certain degrees is calculated through the equation,
                            H = mcpdT
where H is heat, m is mass, cp is specific heat capacity, and dT is change in temperature. From a reliable source, cp for aluminum is equal to 0.215 cal/g°C. Substituting this to the equation,
                               H = (260.5 g)(0.215 cal/g°C)(125°C - 0)
                                        H = 7000.94 cal
6 0
2 years ago
Isotonic compound have high melting point. Why ? Name the ions present in CaS.
yuradex [85]

Explanation:

Because a large amount of energy is required to break the strong inter-ionic attraction.

CaS => Ca2+ & S2-

3 0
3 years ago
What is the area of a medium triangle?​
galben [10]

Answer: Area of a Triangle Equals Base x Height / 3

Explanation: Hope this works

6 0
2 years ago
Calculate the standard free-energy change at 25 ∘C for the following reaction:
lianna [129]

Answer:

Standard free-energy change at 25^{0}\textrm{C} is -3.80\times 10^{2}kJ/mol

Explanation:

Oxidation: Mg(s)-2e^{-}\rightarrow Mg^{2+}(aq.)

Reduction: Fe^{2+}(aq.)+2e^{-}\rightarrow Fe(s)

--------------------------------------------------------------------------------------

Overall: Mg(s)+Fe^{2+}(aq.)\rightarrow Mg^{2+}(aq.)+Fe(s)

Standard cell potential, E_{cell}^{0}=E_{Fe^{2+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}

So, E_{cell}^{0}=(-0.41V)-(-2.38V)=1.97V

We know, standard free energy change at 25^{0}\textrm{C}(\Delta G^{0}): \Delta G^{0}=-nFE_{cell}^{0}

where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol

Here n = 2

So, \Delta G^{0}=-(2)\times (96500C/mol)\times (1.97V)=-380210J/mol=-380.21kJ/mol=-3.80\times 10^{2}kJ/mol

8 0
2 years ago
Read 2 more answers
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