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2 years ago

A student wishes to work out how much power she uses to lift her body when climbing a

Physics

1 answer:

Bess [88]2 years ago

4 0

Answer

i'm not 100% sure but 1764

Explanation:

Work done = gravitational potential energy

Gravitational potential energy = mass(kg) × height(m) × gravitational field strength(N/kg)

We can assume that the student is on earth so the gravitational field strength is 9.8N/kg

So work done = 60 × 3×9.8

=1764

(if you need help calculating power but if you do just divide your answer by 12 and you will get 147)

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A 2-lb slider is propelled upward at A along the fixed curved bar which lies in a vertical plane. If the slider is observed to h

timofeeve [1]

To develop this problem it is necessary to apply the concepts given in the balance of forces for the tangential force and the centripetal force. An easy way to detail this problem is through a free body diagram that describes the behavior of the body and the forces to which it is subject.

PART A) Normal Force.

$F_n = \frac{mv^2}{r}$

$N+mgcos\theta = \frac{mv^2}{r}$

Here,

Normal reaction of the ring is N and velocity of the ring is v

$N+mgcos\theta = \frac{mv^2}{r}$

$N+Wcos\theta = \frac{W}{g} (\frac{v^2}{r})$

$N+2cos30\° = \frac{2}{32.2}*\frac{10^2}{2}$

$N = 1.374lb$

PART B) Acceleration

$F_t = ma_t$

$-mgsin\theta = ma_t$

$-W sin\theta = \frac{W}{g} a_t$

$-2Sin30\° = (\frac{2}{32.2})a_t$

$a_T = -16.10ft/s^2$

Negative symbol indicates deceleration.

<em>NOTE: For the problem, the graph in which the turning radius and the angle of suspension was specified was not supplied. A graphic that matches the description given by the problem is attached.</em>

8 0

3 years ago

Consider a block on a spring oscillating on a frictionless surface. The amplitude of the oscillation is 11 cm, and the speed of

IRISSAK [1]

Answer:

The angular frequency of the block is ω = 5.64 rad/s

Explanation:

The speed of the block v = rω where r = amplitude of the oscillation and ω = angular frequency of the oscillation.

Now ω = v/r since v = speed of the block = 62 cm/s and r = the amplitude of the oscillation = 11 cm.

The angular frequency of the oscillation ω is

ω = v/r

ω = 62 cm/s ÷ 11 cm

ω = 5.64 rad/s

So, the angular frequency of the block is ω = 5.64 rad/s

6 0

3 years ago

Acceleration is the magnitude of average velocity.

lina2011 [118]

Answer:

false

Explanation:

just did the question on apex, true was wrong

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3 years ago

The activation of clotting factors will be blocked.

dedylja [7]

With the blocking of activation of clotting factors, the rate of conversion of fibrinogen to fibrin will decrease to a huge extent and this will prevent the clot formation.

Option A

<h3><u>Explanation:</u></h3>

The process of stopping of flow of blood through any wound by formation of a clot is known as blood clotting. The clot in blood is formed by conversion of the fibrinogen protein into its polymer form fibrin which forms a meshwork.

The conversion of fibrinogen to fibrin requires a lot of enzymes and factors present which is required one by one, known as the Cascade theory. Total of 13 factors are required, where there are prothrombin, thromboplastin, and different other factors. Inactivation of any of the 13 factors will lead to less conversion of fibrinogen to fibrin, thereby the rate of conversion will highly decrease.

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3 years ago

What is the equation for force

Basile [38]

The equation is F=ma :)

3 0

3 years ago

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