Answer:
S = 1/2 Vo t + 1/2 a t^2 = d time for particle to travel distance d
F = E q force acting on particle
a = F / m = E q / m
d = Vo t + E q / (2 m) t^2
One would need to solve the quadratic equation shown to find the time t
t^2 + (2 m) / E q * V0 t - (2 m) / E q * d = 0
or t^2 + A V0 t - A d = 0 where A = (2 m) / E q
Hello There!
From what i know, gravitational force increases if the mass is increased.
If the mass is being decreased, then i assume it will be B. Decreases.
Hope This Helps You!
Good Luck :)
- Hannah ❤
From the given information, we don't know. All we can tell is the net effect of all the changes during those 4 seconds ... the "averages".
The average change in speed is an increase of 72 km/hr (20 m/s) during that time.
The average acceleration is a constant 18 km/hr/sec (5 m/s^2) during the same time.
But both the speed and the acceleration may have gone up or down many times during the 4 seconds.
