Option B.

How many hydrogen atoms are found in two molecules of hydroxylamine, 2NH2OH?

Bogdan [553]

It would be six because in every one molecule, there are three atoms of hydrogen, so just double that and you have six.

6 0

4 years ago

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If a car is travelling 120 miles southbound for 3 hours, what is the velocity?

Zinaida [17]

Answer:

40 miles / hour south

Explanation:

120 miles/3 hours = 40 miles / hour

4 0

3 years ago

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A 7.25 kg7.25 kg block is sent up a ramp inclined at an angle ????=28.5°θ=28.5° from the horizontal. It is given an initial velo

Free_Kalibri [48]

Answer:

15.03 m

Explanation:

Given:

mass of the block, m = 7.25 kg

Angle, Θ = 28.5°

Initial speed of the block, v₀ = 15 m/s

let the distance traveled by the block be 's'

Now, applying the work energy theorem,

we have

$(m\times g\times\sin(\theta)\times s) + \mu_k\times mg\times s\times cos(\theta) = \frac{1}{2}\times m\times v^2$

on substituting the values in the above equation, we get

$(7.25\times 9.8\times\sin(28.5^o)\times s) + 0.326\times 7.25\times9.8\times s\times cos(28.5^o) = \frac{1}{2}\times 7.25\times 15^2$

or

$33.902\times s) +20.35\times s = 815.625$

or

$54.252\times s = 815.625$

s = 15.03 m

Hence, the block will travel 15.03 m up the ramp

6 0

3 years ago

A loaded ore car has a mass of 950 kg and rolls on rails with negligible friction. It starts from rest and is pulled up a mine s

Ierofanga [76]

Answer:

a). P=11.04kW

b). Pmax=11.38 kW

c). Wt=6423.166kJ

Explanation:

The power of the motor when the speed is constant is the work in a determinate time.

$P=\frac{W}{t}$

The work is the force the is applicated in a distance so

W=F*d

replacing:

$P=F*\frac{d}{t}$ and $\frac{d}{t}$ determinate distance in time is velocity so

a).

$P=F*v$

$F=m*a\\F=m*g*sin(33.5)$

$P=950kg*9.8\frac{m}{s^{2}}*sin(33.5)*2.15\frac{m}{s}\\P=11047.846 W\\P=11.0478 kW$

b).

The maximum power must the motor provide, is the maximum force with the maximum speed of the motor in this case

The first step is find the acceleration so

$vi=0\frac{m}{s} \\vf=2.15 \frac{m}{s}\\vf=vi+a*t\\vf-vi=a*t\\ a=\frac{vf-vi}{t}= a=\frac{2.15\frac{m}{s}-0\frac{m}{s}}{13s}\\a=0.1653 \frac{m}{s^{2}}$

The maximum force is when the car is accelerating so

$Ft=Fa+Fg\\Ft=m*a+m*g*sin(33.5)\\Ft=950kg*0.1653\frac{m}{s^{2}}+950*9.8\frac{m}{s^{2}}*sin(33.5)\\Ft=5295.565 N$

so the maximum force is the maximum force by the maximum speed

$Pmax=Ft*v\\Pmax=5295.565N*2.15\frac{m}{s}\\Pmax=11385.46\\Pmax=11.3854kW$

c).

The total energy transfer without any friction is the weight move in the high axis y in this case, so is easy to know that distance

W=m*g*h

h=Length*sin(33.5)

W=m*g*Length*sin(33.5)

W=950 kg*9.8* 1250m*sin(33.5)

W=6423166.667 kJ

W=6423.166 kJ

4 0

4 years ago

In the future, people will only enjoy one sport: Electrodes. In this sport, you gain points when you cause metallic discs hoveri

pochemuha

Answer:

Disk C and Disk D

Explanation:

The total charge in the disks

$q_1 + q_2 = q_{total}$

must be conserved before and after bringing them together.

Lets equate the sum of the initial charge with the sum of the final for the disk:

$q_{1_i} + q_{2_i} = q_{1_f} + q_{2_f} = 2 * (+8.5) \mu C$

$q_{1_i} + q_{2_i} = +17 \mu C$

So, the initial charges must sum +17 μC.

Now, as there are no charges over +17 μC, this means that both charges must be positive.

As the only positive charges are $q_C$ and $q_D$ , this disk must be the ones we are looking for. And, as we can see, they sum 17 μC:

$q_{C} + q_{D} = 5 \mu C + 12 \mu C = 17 \mu C$

3 0

3 years ago