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Olenka [21]
3 years ago
7

What happens to the boat when its weight is greater than the buoyant force?

Physics
1 answer:
oee [108]3 years ago
3 0

Answer:

1. and 2. If the buoyant force is greater than the object's weight, the object rises to the surface and floats. If the buoyant force is less than the object's weight, the object sinks. If the buoyant force equals the object's weight, the object can remain suspended at its present depth.

3. When the buoyant force equals one ton, it will sink no further. When any boat displaces a weight of water equal to its own weight, it floats. This is often called the “principle of flotation” where a floating object displaces a weight of fluid equal to its own weight.

Explanation:

Can anyone help me with my history question.

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Convert the mass to kgs thanks
Natali [406]
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4 0
3 years ago
how does inertia explain the movement of your body when a car in which you are riding comes to a sudden stop? (8 sentences)
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5 0
3 years ago
Consider 3.5 kg of austenite containing 0.95 wt% c and cooled to below 727°c (1341°f). (a) what is the proeutectoid phase? (b) h
vladimir2022 [97]
A. The proeutectoid phase is Fe₃c because 0.95 wt/c  is greater than the eutectoid composition which is 0.76 wt/c

b.  We determine how much total territe and cementite form, we apply the lever rule expressions yields.
Wx = (fe₃c-co/cfe₃ c-cx = 6.70- 0.95/6.70- 0.022 = 0.86
The total cementite
Wfe₃C = 10-Cx/ Cfe₃c -Cx = 0.95 - 0.022/6.70 - 0.022 = 0.14
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c.  We calculate the pearule and the procutectoid phase which cementite form the equation
Ci = 0.95 wt/c
Wp = 6.70 -ci/6.70 - 0.76 = 6.70 -0.95/6.70 - 0.76 = 0.97
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4 0
3 years ago
Snorkelers breathe through tubes that extend above the surface of the water. In prin- ciple, a snorkeler could go deeper with a
Yanka [14]

Answer:

h = 1.02 m

Explanation:

This is a fluid mechanics exercise, where the pressure is given by

       P = P_{atm} + ρ g h

The gauge pressure is

      P - P_{atm}  = ρ g h

In this case the upper part of the tube we have the atmospheric pressure. and the diver can exert a pressure 10 KPa below the outside pressure, this must be the gauge pressure

     P_{m} =    P - P_{atm}

     P_{m} = ρ g h

     h =P_{m} / ρ g

calculate

     h = 10 103 / (1000 9.8)

     h = 1.02 m

This is the depth at which man can breathe

8 0
3 years ago
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