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erastovalidia [21]
3 years ago
14

What will happen to the equilibrium between carbonic acid and bicarbonate if I add a strong base to this system?

Chemistry
1 answer:
Helen [10]3 years ago
3 0

Answer:

The equilibrium will shift in forward direction.

Explanation:

The equilibrium between the carbonic acid and bicarbonate ion is shown below as:

H₂CO₃ (aq) ⇔ H⁺(aq) + HCO₃²⁻(aq)

According to Le Chatelier's Principle, the change in any state of the equilibrium say temperature, volume, pressure, or the concentration, the equilibrium will oppose these changes and will shift in such a way that the effect cause must be nullified.

<u>If a strong base is added to the equilibrium, the base will accept hydrogen ions which are formed in the right side of the equilibrium. Thus, there will be less hydrogen ions present and to compensate this effect, the equilibrium will shift in forward direction.</u>

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A sample of oxygen gas occupies 3.60 liters at a pressure of 1.00 atm. If temperature is held constant, what will be the volume
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Answer: The volume of the oxygen gas at a pressure of 2.50 atm will be 1.44 L

At constant temperature, the volume of a fixed mass of gas is inversely proportional to the pressure it exerts, then

PV = c

Thus, if the pressure increases, the volume decreases, and if the pressure decreases, the volume increases.

It is not necessary to know the exact value of the constant c to be able to use this law since for a fixed amount of gas at constant temperature, it is satisfied that,

P₁V₁ = P₂V₂

Where P₁ and P₂ as well as V₁ and V₂ correspond to pressures and volumes for two different states of the gas in question.

In this case the first oxygen gas state corresponds to P₁ = 1.00 atm and V₁ = 3.60 L while the second state would be P₂ = 2.50 atm and V₂ = y. Substituting in the previous equation,

1.00 atm x 3.60 L = 2.50 atm x y

We cleared y to find V₂,

V₂ = y = \frac{1.00 atm x 3.60 L}{2.50 atm} = 1.44 L

Then, <u>the volume of the oxygen gas at a pressure of 2.50 atm will be 1.44 L</u>

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Explanation:

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Symbol: Ta

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Atomic Mass: 180.9479 amu

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Boiling Point: 5425.0 °C (5698.15 K, 9797.0 °F)

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Number of Neutrons: 108

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