Answer:
1170 km/hr
Explanation:
Let's first state the formula to be used
c = √(KRT)
The temperature at an altitude of 15km is -56.5° C
Let's not convert this to °K, we have
-56.5° + 273.15 = 216.65° K
Also, the temperature at 8km is -36.9° C, on converting to °K we have
-36.9° + 273.15 = 236.25° K
Then again, we look for the speed at both 15 km and 8 km both of which are 295 m/s and 308 km
Finally, we use the mach similarity formula
(V/c) of 15km = (V/c) of 8km
V of 8km = c of 8km * (V/c) of 15km
V of 8km = 1170 km/hr
