Explanation:
I don't know I'm so sorry
Answer:11.602 KW
Explanation:
mass of vehicle
speed=40Km/h
Resistance=600 N

Gear ratio

Net force to overcome by engine is
F=Resistance + sin component of weight
F=600+
Where ![tan\theta =[tex]\frac{1}{50}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%5Btex%5D%5Cfrac%7B1%7D%7B50%7D)


F=600+235.38=835.38 N
power=
Engine Power=
=11.602 KW
Answer:
248.756 mV
49.7265 µA
Explanation:
The Thevenin equivalent source at one terminal of the bridge is ...
voltage: (100 V)(1000/(1000 +1000) = 50 V
impedance: 1000 || 1000 = (1000)(1000)/(1000 +1000) = 500 Ω
The Thevenin equivalent source at the other terminal of the bridge is ...
voltage = (100 V)(1010/(1000 +1010) = 100(101/201) ≈ 50 50/201 V
impedance: 1000 || 1010 = (1000)(1010)/(1000 +1010) = 502 98/201 Ω
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The open-circuit voltage is the difference between these terminal voltages:
(50 50/201) -(50) = 50/201 V ≈ 0.248756 V . . . . open-circuit voltage
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The current that would flow is given by the open-circuit voltage divided by the sum of the source resistance and the load resistance:
(50/201 V)/(500 +502 98/201 +4000) = 1/20110 A ≈ 49.7265 µA