Answer:
Protons
Explanation:
Protons are the subatomic particle that determines the identity of an element.
Answer:
look at the graph
Explanation:
We know that as temperature increases, solubility increases.So, when there is a rise in temperature, as more solute become dissolved, the saturation point will be lifted and more amount of solute will be needed to reach saturation.
Here, when the temperature was 20oC, 38 g of salt was needed for saturation. As the temperature is increased by 15oC, at 35oC more amount of salt was needed to reach saturation(45g). So a 15oC rise in temperature caused a 7 g rise in the amount of salt needed for saturation. So, if temperature is increased additionally through 10oC, an approximate 4.5 g of salt will be needed more to reach the saturation. That is at 45oC, the amount of salt at saturation will be approximately 49.5 g.
So, the temperature and solubility as well as temperature and amount of salt at saturation are linearly related(directly proportional)
Answer:
Adiabatic temperature changes.
Explanation:
Temperature changes related to changes of pressure without external gain or loss of heat. If no heat is added or lost to the surroundings, then when an air parcel rises and expands, its temperature drops. Conversely, when the parcel is compressed, its temperature rises. So the term adiabatic, implies a change in temperature of the air parcel without gain or loss of heat from outside the air parcel.
Answer:
The answer to your question is No, it is not.
Explanation:
Data
C₄H₁₀ + 13O₂ ⇒ 8CO₂ + 10H₂O
In a double replacement reaction, two reactants interchange cations an example of these reactions are neutralization reactions. In neutralization reactions, an acid and a base react to form a salt and water.
The reaction of this problem is not a double replacement reaction because the products are carbon dioxide and water, not a salt and water.
The reaction of this problem is a combustion reaction.
Answer:
To calculate the Carbon Dioxide - CO 2 - emission from a fuel, the carbon content of the fuel must be multiplied with the ratio of molecular weight of CO 2 (44) to the molecular weight of Carbon (12) -> 44 / 12 = 3.7 Emission of CO 2 from combustion of some common fuels are indicated in the table
Explanation:
