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Helga [31]
3 years ago
7

Si un astronauta tiene una masa de 72kg si el valor de g en la luna es 1.6m/s2, ¿cual es la fuerza gravitacionar de la luna sobr

e el astronauta?​
Physics
1 answer:
Fantom [35]3 years ago
5 0

(72 kg) (1.6 m/s²) = 115.2 kg • m/s² = 115.2 N

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A 75.5 kg diver drops from a diving board 10.0 m above the waters surface. Find the divers speed just before he strikes the wate
jenyasd209 [6]

Answer:

<em>v=14 m/s</em>

Explanation:

<u>Mechanical Energy </u>

The kinetic energy of a body (K) is the capacity of doing work due to its speed. It can be expressed as

\displaystyle K=\frac{mv^2}{2}

The potential energy (U) is the capacity of doing work due to its height respect to a certain reference level.

U=mgh

The  mechanical energy is the sum of both

\displaystyle E_m=\frac{mv^2}{2}+mgh

The principle of conservation of mechanical energy states it must remain the same if no external force is acting on it. The diver drops from the diving board, which means its initial speed is zero (and so its initial kinetic energy). Thus, the mechanical energy at the jumping time is

\displaystyle E_m=mgh=(75)(10)(9.8)=7350\ J

When the diver is about to get into the water, his height reaches zero and the speed is at maximum. All the potential energy became kinetic energy, so

\displaystyle \frac{mv^2}{2}=7350\ J

Rearranging

\displaystyle v^2=\frac{2(7350)}{75}=196

v=\sqrt{196}=14\ m/s

The final speed of the diver is

\boxed{v=14\ m/s}

8 0
3 years ago
Suppose you hit a 0.058-kg tennis ball so that the ball then moves with an acceleration of 10 m/s2. If you were to hit a basketb
stiks02 [169]

Answer:

1 m/s²

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Force = mass × acceleration

F = ma ............ Equation 1

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F = m'a

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Given: F = 0.58 N, m' = 0.58 kg.

Substitute into equation 2

a = 0.58/0.58

a = 1 m/s²

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Answer:

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Explanation:

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