<u>Answer:</u>
∠VWT = 131°
<u>Explanation:</u>
∠VWT is equal to ∠UTW because they are Alternate inner angles. Since they are equal, we know that the measure of ∠VWT is 131°.
Hoped this helped!
Answer:
Draw a 3-D of a terrain indicating different fault behaviors. Use the terrain below. Be sure that the entire terrain should cover at least three type of fault. Labcl the fault arcas and its part
The range is the ouutput from inputing the input
basically
25=k²+2k+1 and 64=k²+2k+1
the values that satisfy both equations (not at the same tim) are the valuess that are the domain
solve each
25=k²+2k+1
minus 25 both sides (or recognize the perfect square trinomial, but anyway)
0=k²+2k-24
factor
0=(k+6)(k-4)
set to zero
k+6=0
k=-6
k-4=0
k=4
k=-6 or 4
64=k²+2k+1
minus 64 both sides
0=k²+2k-63
facor
0=(k-7)(k+9)
set to zer
k-7=0
k=7
k+9=0
k=-9
k=-9 or 7
so the domain has the numbers
-9,-6,4,7
it seems we only want the positive square roots so
answer is {4,7} is the domain
Answer:
i thinks the answer is the fourth, which an= 3-2(n-1)
Answer:
n° = 62°
p° = 62°
q° = 118°
v° = 84°
w° = 138°
Step-by-step explanation:
angle ABC is 118°
so
m° + 118° = 180
m° = 180° - 118°
m° = 62°
n° = m° = 62° (corresponding angles are equal since AB is parallel to DC, and BC)
p° = n° = 62° (vertical angles are equal)
q° + n° = 180° (linear pair angles)
q° + 62° = 180°
q° = 180° - 62°
q° = 118°
v° + 96° = 180° (linear pair angles)
v° = 180° - 96°
v° = 84°
w° + 42° = 180 (linear pair angles)
w° = 180° - 42°
w° = 138°
