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3 years ago

8

A 4-kg object is moving with a speed of 5 m/s at a height of 2 m. The kinetic

1 answer:

tatyana61 [14]3 years ago

7 0

Hello!

$\large\boxed{KE = 50J}$

Use the formula for kinetic energy:

$KE = \frac{1}{2}mv^{2}$

Plug in the given mass and velocity:

$KE = \frac{1}{2} (4)5^{2}$

Simplify:

$KE = \frac{1}{2} (100)\\\\KE = 50 J$

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What is your interpretation of 'nothing'? (Talking astrophysics) More answers the better!

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3 years ago

If a star has no measurable parallax, what can you infer?.

Leni [432]

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3 years ago

Show your work please

nekit [7.7K]

Answer:

$V = U + at$

Explanation:

<u>Given the following data;</u>

Initial velocity = 0 (since the stone is starting from rest).

Final velocity = 32 m/s

Acceleration = g = 10 m/s²

Time = 3.2 seconds

To show that the speed of the stone when it hits the ground is 32 m/s, we would use the first equation of motion;

$V = U + at$

Where;

V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.

Substituting into the formula, we have;

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3 years ago

a bag of cement is pulled along a horizontal plane by a constant force of 15n calculate the work done in moving the bag through

morpeh [17]

Answer:

300J

Explanation:

Given parameters:

Constant force = 15N

Distance = 20m

Unknown:

Work done = ?

Solution:

Work done is the force applied to move a body through a particular distance.

Work done = Force x distance

So;

Work done = 15 x 20 = 300J

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3 years ago

A 2640-Hz sound source is moving at 15.0m/s toward a stationary observer. What is the frequency heard by the observer if the spe

Dvinal [7]

Answer:

The frequency heard by the observer is 2760.73 hertz. Explanation:

Frequency of source, f = 2640 Hz

Velocity of source, $v_s=15\ m/s$

The speed of sound, v = 343 m/s

Let f' is the frequency heard by the observer. According to Doppler's effect, the frequency of the observer is given by :

$f'=\dfrac{fv}{v-v_s}$ (as the source is moving towards observer)

$f'=\dfrac{2640\times 343}{343-15}$

f' = 2760.73 Hz

So, the frequency heard by the observer is 2760.73 hertz. Hence, this is the required solution.

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4 years ago