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2 years ago

PLEASE HELP!!!

Chemistry

1 answer:

chubhunter [2.5K]2 years ago

3 0

Answer:

Two design criteria for the design of the ammonia making process are;

1) Sustainable hydrogen production by renewable energy

2) Sustainable use of the ammonia-water thermal absorption cycle to retrieve the ammonia present in the waster water

Explanation:

Ammonia is produced from natural gas in the following process;

H₂ + RSH → RH + H₂S

H₂S + ZnO → ZnS + H₂O (Waste water)

CH₄ + H₂O → CO + 3H₂

CO + H₂O → CO₂ + H₂

Ammonia is then produced by reacting the produced hydrogen with nitrogen in the presence of a catalyst in a process known as the Haber-Bosch process as follows;

3H₂ + N₂ → 2NH₃

The

The design criteria for the design of the ammonia making process therefore as follows;

1) Sustainable use of renewable energy to produce hydrogen gas from the electrolysis of water

2) Use of the ammonia-water thermal absorption cycle to retrieve the ammonia present in the waster water.

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Answer:

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Explanation:

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2 years ago

Heating 2.40 g of the oxide of metal X (molar mass of X = 55.9 g/mol) in carbon monoxide (CO) yields the pure metal and carbon d

Korolek [52]

Answer:The molecular formula of the oxide of metal be $X_2O_3$ . The balanced equation for the reaction is given by:

$X_2O_3+3CO\rightarrow 3CO_2+2X$

Explanation:

Let the molecular formula of the oxide of metal be $X_2O_y$

$X_2O_y+yCO\rightarrrow yCO_2+2X$

Mass of metal product = 1.68 g

Moles of metal X = $\frac{1.68 g}{55.9 g/mol}=0.03005 mol$

1 mol of metal oxide produces 2 moles of metal X.

Then 0.03005 moles of metal X will be produced by:

$\frac{1}{2}\times 0.03005 mol=0.01502 mol$ of metal oxide

Mass of 0.01502 mol of metal oxide = 2.40 g (given)

$0.01502 mol\times (2\times 55.9 g/mol+y\times 16 g/mol)=2.40 g$

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The molecular formula of the oxide of metal be $X_2O_3$ . The balanced equation for the reaction is given by:

$X_2O_3+3CO\rightarrow 3CO_2+2X$

8 0

2 years ago

What is the difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm

Zanzabum

Answer:

The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :

Difference in mass = 985.32 - 984.5 = 0.82 g

Explanation:

Part I :

$n =\frac{3.01\times 10^{24}}{6.022\times 10^{23}}$

n = 4.9983

n = 4.99 moles

(Note : You can also take n = 5 mole )

Molar mass of gold = 196.96 g/mole

This means, 1 mole of gold(Au) contain = 196.96 grams

So, 4.99 moles of gold contain = $5\times 196.96$ g

4.99 moles of gold contain = 984.8 g

Mass of ${3.01\times 10^{24}}$ atoms of gold = 984.5 g

Part II :

Density of Gold = $19.32 g/cm^{3}$

Volume of the cuboid = $length\times breadth\times height$

Volume of the gold bar = $6.00\times 4.25\times 2.00$

Volume of the gold bar = 51 $cm^{3}$

Using formula,

$Density = \frac{mass}{Volume}$

$Mass = Density\times Volume$

$Mass = 19.32 \times 51$

Mass = 985.32 g

So, A gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm has mass of 985.32 g

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3 0

2 years ago

Why are valence electrons important?

Usimov [2.4K]

They are the outer layer of the electron layers.

5 0

2 years ago

Read 2 more answers

In a mixture of 2 ideal gases, A and B, PA = 0.2PB, what is the mole fraction of A?

Alborosie

Answer:

0.1667

Explanation:

Hello,

Dalton's law defines:

$y_i=\frac{P_i}{P_T}$

A total pressure is:

$P_T=P_A+P_B$

So, for A (solving for $P_A$ in the previous equation, we get:

$y_A=\frac{P_A}{P_A+P_B}$

Since $P_A=0.2P_B$ , we obtain:

$y_A=\frac{P_A}{P_A+P_A/0.2}\\y_A=\frac{1}{6}\\y_A=0.1667$ }

Best regards.

7 0

2 years ago