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3 years ago

Help! Drag and drop the answer into the box to match each method of how to separate solutions to its description.

Chemistry

1 answer:

Flura [38]3 years ago

7 0

Answer:

1) D 2) A 3) C

Explanation:

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How is energy transfer different from energy transformation?

stepan [7]

Answer:

Transformation is into a different type of energy Ex: chemical to physical

Transfer is going to a to a place Ex: door knob to you

Explanation:

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5 0

2 years ago

The atom shown below is?

Volgvan

Answer:

Explanation:

Not likely to form any bonds because in it's last she'll it has 8 electrons and is therefore stable

8 0

2 years ago

How much heat (in kj) is required to warm 13.0 g of ice, initially at -12.0 ∘c, to steam at 113.0 ∘c? the heat capacity of ice i

olga nikolaevna [1]

The total amount of heat required is the sum of all the sensible heat and latent heats involved in bringing the ice to a desired temperature and state. The latent heat of fusion and vaporization of water 333.55 J/g and 2260 J/g, respectively. Solving for the total amount of heat,
total amount of heat = 13.0 g (2.09 J/gC)(12) + 13(333.55 J/g) + 13.0 g (4.18 J/gC)(100 - 0) + (13.0 g)(2260 J/g) + (13 g)(2.01 J/g)(113-100)
= 39815.88 J
= 39.82 kJ

5 0

3 years ago

Read 2 more answers

11.<br> The electron configuration for phosphorous is [Ar]3s23p4.<br> TRUE<br> FALSE

user100 [1]

Answer:

False

Explanation:

Phosphorus is number 15 on the periodic table, so its electronic configuration is:

${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{3}$

5 0

2 years ago

When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at

STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

$1.22 * 10^{5} = - 8.314* 2400 * ln K$

$\\ 1.22 * 10^{5} = -19953.6 * ln K$

$ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022$

So, the equilibrium constant is 0.0022.

4 0

3 years ago