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makvit [3.9K]
3 years ago
8

Which of the following is not a step in balancing redox reactions in acidic solution, using the half-reaction method?

Chemistry
2 answers:
schepotkina [342]3 years ago
7 0
B <span>Divide the chemical equation into two half-reaction equations, identifying which half-reaction is oxidation and which is reduction 
</span>
marishachu [46]3 years ago
3 0

Answer:

The answer would be A). H2O and OH- are added as needed to the half-reaction equations to make the number of oxygen and hydrogen atoms balance.

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The octet rule states that, in chemical compounds, atoms tend to have _____.
olga nikolaevna [1]

The correct answer is C


4 0
3 years ago
How do catalysts function? A. They protect the products from external reactions. B. They increase the activation energy of an el
tamaranim1 [39]
The answer is C. They lower the activation energy of an elementary step of a reaction
This makes the reaction rate to increase since less energy is required to make a reaction occur.
3 0
3 years ago
What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?
Westkost [7]
PV=nRT

P=nRT/V

P=[(0.650mol)(0.08206)(298K)]/(0.750L)=21.2atm



6 0
3 years ago
Which of the following isoelectronic series is correctly ranked from largest ionic radius to smallest ionic radius? 1. N 3−, O 2
love history [14]

Answer:

<u>Option 1</u>:  N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²    

Explanation:

<u>Ionic radius is the radius of an atom´s ion in ionic crystal structure</u>.<u> </u><u><em>In an ion that lose an electron, to form a cation, the radius of the ion gets smaller</em></u><em>, </em>because the repulsion between electrons decrease because fewer electrons are present. Conversely, <u><em>adding on electron to a neutral atom, to form an anion, causes electron - electron repulsions to increase, so the size of the radius of the ion gets bigger.</em></u>                  

<u><em>Isoelectronic species are ions or elements that have the same number of electrons in their electronic shells but have different overall charges, because of their different atomic numbers</em></u>.                        

<u><em>In a isolelectronic series (same number of electrons),</em></u> <u><em>the increase of the positive charge (given by the number of protons in the nucleus), will cause a decrease in radius </em></u>beacuse the greater electrostatic attraction between the electrons and the nucleus. Consequently, the ion with the greatest nuclear charge will have the smallest ionic radius and the ion with the smallest nulear charge will have the largest ionic radius.  

<u>We will use this principle to solve our problem</u>.  

In our case, the given ions are:  

  • N⁻³ :    Z = 7,  e⁻ = 10
  • O⁻²:     Z= 8,   e⁻ =10
  • F⁻:       Z = 9,  e⁻ = 10
  • Na⁺:    Z= 11,   e⁻ = 10
  • Mg⁺²:  Z=12,   e⁻ =10

where Z= number of protons, and e⁻ = number of electrons.

<em><u>Hence the decreasing order of ionic radius is:</u></em>

N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²  

Have a nice day!

4 0
3 years ago
Solid aluminum metal and diatomic bromine liquid react spontaneously to form a solid product. give the balanced chemical equatio
kaheart [24]
Aluminum has a chemical formula of Al, while diatomic bromine has a chemical formula of Br₂. The balanced chemical reaction is shown below:

<em>2 Al (s) + 3 Br₂ (l) → 2 AlBr₃ (s)</em>

The solid product is called Dibromoaluminum. The stoichiometric coefficients are used to balance the reaction to obey the Law of Conservation of Mass.
3 0
3 years ago
Read 2 more answers
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