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ra1l [238]
2 years ago
7

How do we balance a chemical equation 4 marks?.

Chemistry
1 answer:
Vesna [10]2 years ago
6 0

To balance a chemical equation, place coefficient as needed in front of the symbols or formulas of the elements. So the same number of each type of atom occurs in both reactants and products.

Steps to be followed are-

(1) Write down the chemical reaction in the form of word equation, keeping all the reactants on left hand side and keeping products on right hand side.

(2) Write all the symbol and formula of all reactants and products in word equation.

(3) Balance the whole equation by multiplying the symbols and formula by smallest possible figures.

Same number of each and every atom, of same type occurs in both reactants and products.

Once all the individual elements are balanced, then the total number of atoms of each element on the reactant and product side are compared once again after balancing. If there are no inequalities, the chemical equation is said to be balanced.

To learn more about balancing chemical equations visit the link- brainly.com/question/26227625

#SPJ4

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Is it possible for two yellow belied noombats to have a green bellied child?
Ivahew [28]
<span> If both of them has </span>yellow<span> as the dominant trait, then </span>green<span> may be recessive. In that case there is a chance for them to </span>have a green bellied child<span>.

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5 0
4 years ago
Oxidation unit test
3241004551 [841]

In this case, according to the given information about the oxidation numbers anf the compounds given, it turns out possible to figure out the oxidation number of manganese in both MnI2, manganese (II) iodide and MnO2, manganese (IV) oxide, by using the concept of charge balance.

Thus, we can define the oxidation state of iodine and oxygen as -1 and -2, respectively, since the former needs one electron to complete the octet and the latter, two of them.

Next, we can write the following x, since manganese has five oxidation states, and it is necessary to calculate the appropriate ones:

Mn^xI_2^-\\\\Mn ^xO_2^{-2}

Next, we multiply each anion's oxidation number by the subscript, to obtain the following:

Mn^xI_2^-\rightarrow x-2=0;x=+2\\\\Mn ^xO_2^{-2}\rightarrow x-4=0;x=+4

Thus, the correct choice is Manganese has an oxidation number of +2 in Mnl2 and +4 in MnO2.

Learn more:

  • brainly.com/question/15167411
  • brainly.com/question/6710925
8 0
3 years ago
Several balls and sticks glued together to represent a molecule
rewona [7]

Answer:

The different elements are represented by their symbols one line shows a single bond and two lines show a double bond. This written representation is called a structural diagram

4 0
3 years ago
A sample of a monoprotic acid (ha) weighing 0.384 g is dissolved in water and the solution is titrated with aqueous naoh. if 30.
posledela
The formula for the monoprotic acid is taken as HA, reaction with base is as follows;
HA + NaOH ---> NaA + H₂O
Stoichiometry of acid to base is 1:1
At the neutralisation point, number of HA moles = number of base moles
Number of NaOH moles reacted = 0.100M / 1000 mL /L x 30.0 mL = 0.003 mol
Therefore number of HA moles reacted = 0.003 mol
the mass of acid 0.384 g
Therefore molar mass - 0.384 g/ 0.003 mol = 128 g/mol
3 0
3 years ago
What is the first step to determine the sequence of filling electron configurations of an element?
faust18 [17]
Basically, the arrangement of electrons in electronic configuration follows three principles:

1. Aufbau Principle
You start from the highest energy level to the lowest. The arrangement is: <span>1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p<7s<5f<6d<7p.

2. Hund's Rule
Each box in the configuration can hold up to 2 electrons. This rule tells you to fill all boxes of one particular subshell with 1 electron first, before double occupying them.

3. Pauli's Exclusion Principle
This rule tells you that the two electrons in a box shall always have opposite spins, represented by one half-arrow up and one half-arrow down.</span>
6 0
3 years ago
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