To solve this problem we will use the trigonometric concepts to find the distance h, which will allow us to find the speed of Jeff and that will finally be the variable that will indicate the total tension, since it is the variable of the centrifugal Force given in the vine at the lowest poing of the swing.
From the image:


When Jeff reaches his lowest point his potential energy is converted to kinetic energy





Tension in the string at the lowest point is sum of weight of Jeff and the his centripetal force




Therefore the tension in the vine at the lowest point of the swing is 842.49N
Answer: 0 m
Explanation:
Let's begin by stating clear that movement is the change of position of a body at a certain time. So, during this movement, the body will have a trajectory and a displacement, being both different:
The trajectory is the <u>path followed by the body</u> (is a scalar quantity).
The displacement is <u>the distance in a straight line between the initial and final position</u> (is a vector quantity).
According to this, in the description Matthew's home is placed at 0 on a number line, then he moves 10 m to the park (this is the distance between the park and Mattew's home), then 15 m to the movie theatre until he finally comes back to his home (position 0). So, in this case we are talking about the <u>path followed by Matthew</u>, hence <u>his trajectory</u>.
However, if we talk about Matthew's displacement, we have to draw a straight line between Matthew's initial position (point 0) to his final position (also point 0).
Now, being this an unidimensional problem, the displacement vector for Matthew is 0 meters.
The frequency f of the AC source is determined as 0.446 Xc.
<h3>
Frequency of the AC source</h3>
The frequency of the AC source is calculated as follows;
Xc ≡ 1/2fC
where;
- Xc is the capacitive reactance
- f is frequency
- C is capacitance
fC = 2Xc
f = 2Xc / C
f = (2Xc)/4.48
f = 0.446 Xc
Thus, the frequency f of the AC source is determined as 0.446 Xc.
Learn more about frequency here: brainly.com/question/10728818
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Answer: a) 5965.2N b) 379.2N c) 29.37m/s
Explanation: shown in the attachment