Answer:
Explanation:
Given
speed of Electron
final speed of Electron
distance traveled
using equation of motion
where v=Final velocity
u=initial velocity
a=acceleration
s=displacement
acceleration is given by
where q=charge of electron
m=mass of electron
E=electric Field strength
Answer:
E=
Explanation:
We are given that
Charge on ring= Q
Radius of ring=a
We have to find the magnitude of electric filed on the axis at distance a from the ring's center.
We know that the electric field at distance x from the center of ring of radius R is given by
Substitute x=a and R=a
Then, we get
Where K=
Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center=